Can you also please help w F?F: Determine the direction of the velocity of the sandbag at a time 1.30 ss after its release. A hot-air balloonist, rising vertically with a constant velocityof magnitude v = 5.00 m/s, releases a sandbag at aninstant when the balloon is a height h = 40.0 m above theground (Figure 1). After it is released, the sandbag is infree fall. For the questions that follow, take the origin of thecoordinate system used for measuring displacements to bePart DCompute the position of the sandbag at a time 1.30 s after its release.Express your answer in meters.at the ground, and upward displacements to be positive.ΑΣφ.?y =mSubmitRequest AnswerFigure1 of 1Part EA0 - 5.00 m/sCompute the magnitude of the velocity of the sandbag at a time 1.30 s after its release.Express your answer in meters per second.?v =m/sSubmitRequest Answer40.0 m to ground

Name: Can you also please help w F?F: Determine the direction of the velocit
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: Can you also please help w F?F: Determine the direction of the velocity of the sandbag at a time 1.30 ss after its release. A hot-air balloonist, rising vertically with a constant velocityof magnitude v = 5.00 m/s, releases a sandbag at aninstant whe

While solving the question, we need to be very careful about the direction. We will take the upward direction as positive and downward as negative.When the sandbag is dropped, its initial velocity is basically the velocity of the ballon i.e. u=+5 m/s (upward). Its initial height is h0=40 m from the ground. Find its position after t=1.3 s using the formula: h=h0+ut-12gt2 This gives us: h=h0+ut-12gt2h=(40 m)+(5 m/s)(1.3 s)-12×(9.8 m/s2)(1.3 s)2 h=38.219 m Hence, after 1.3 s, the position of the bag is 38.219 m up from the ground.Find the magnitude of the velocity after 1.3 s using the formula: v=u-gt; this gives us: v=u-gtv=(5 m/s)-(9.8 m/s2)(1.3 s)v=-7.74 m/s Hence, after 1.3 s, the magnitude of the velocity is 7.74 m/s and the -ve shows the direction is downward.