2.) A subway train starts from rest at a station and accelerates at a rate of 2.50 mls for 15.90 seconds. H then runs at a constant speed of 35 seconds and then slows down at a rate of 4.50 ml s until it sto ps at the next station? 0) what is the speed of the train to finish th before It starts slo wing. down? Given: Solution Vi 0mls a: 2.50 m Is? At 15-90 seconds Ve: (o mls) + (2.50.mls²)(15.90 s). 39.75 m Is Requined: #: ? Equation: Vf = Vi + a At. b) How long did it take the frain to finish the trip from one station to the other ?
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
![2.) A subway train starts from rest at a station and accelerates at a
rate of 2.50 mls for 15.9b seconds. H then runs at a constant specd of
35 seconds and then slows down at a rate of 4.50 ml s² until it sto ps at
the next station?
Q) what is the speed of the frain to finish tħ before It starts slo wing
down?
Given:
Solution:
Vi: o mis
a: 2.50 m Is²
At:15.90 seconds.
Vp: (o mls) + (2.50 mls²)( 15.90 s)
:
39.75 mls
Requined:
Equation:
Vf = Vi t a At
%3D
b.) How long did it take the train to finish the trip from one station
to the other ?
Given:
Vf= 39.75 mls
t1= 15.90 s
solution
0: 39.75 mls - 4.50 ml S*ts
: 4.50 m Is² to=89.75 mls =
to: 39.75 m ls
4.50 mlsz
: 8.83s
Requinud:
Total time (t)
t: s t 8.83 s
15.90s 35S
59.73s
Equation:
t: tit tz t t3
to: Vf.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d88fde0-ef83-4725-b720-fa16fc721f3d%2F34445d08-59cb-4001-aaf9-1e89cc05234b%2Fwc7zfac_processed.jpeg&w=3840&q=75)
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