2.) A subway train starts from rest at a station and accelerates at arate of 2.50 mls for 15.9b seconds. H then runs at a constant specd of35 seconds and then slows down at a rate of 4.50 ml s² until it sto ps atthe next station?Q) what is the speed of the frain to finish tħ before It starts slo wingdown?Given:Solution:Vi: o misa: 2.50 m Is²At:15.90 seconds.Vp: (o mls) + (2.50 mls²)( 15.90 s):39.75 mlsRequined:Equation:Vf = Vi t a At%3Db.) How long did it take the train to finish the trip from one stationto the other ?Given:Vf= 39.75 mlst1= 15.90 ssolution0: 39.75 mls - 4.50 ml S*ts: 4.50 m Is² to=89.75 mls =to: 39.75 m ls4.50 mlsz: 8.83sRequinud:Total time (t)t: s t 8.83 s15.90s 35S59.73sEquation:t: tit tz t t3to: Vf.

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Description: 2.) A subway train starts from rest at a station and accelerates at arate of 2.50 mls for 15.9b seconds. H then runs at a constant specd of35 seconds and then slows down at a rate of 4.50 ml s² until it sto ps atthe next station?Q) what is the speed

Given: The rate of acceleration is 2.50 m/s2. The time duration is 15.90 s. The rate of deceleration…

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2.) A subway train starts from rest at a station and accelerates at a rate of 2.50 mls for 15.90 seconds. H then runs at a constant speed of 35 seconds and then slows down at a rate of 4.50 ml s until it sto ps at the next station? 0) what is the speed of the train to finish th before It starts slo wing. down? Given: Solution Vi 0mls a: 2.50 m Is? At 15-90 seconds Ve: (o mls) + (2.50.mls²)(15.90 s). 39.75 m Is Requined: #: ? Equation: Vf = Vi + a At. b) How long did it take the frain to finish the trip from one station to the other ?

2.) A subway train starts from rest at a station and accelerates at a rate of 2.50 mls for 15.90 seconds. H then runs at a constant speed of 35 seconds and then slows down at a rate of 4.50 ml s until it sto ps at the next station? 0) what is the speed of the train to finish th before It starts slo wing. down? Given: Solution Vi 0mls a: 2.50 m Is? At 15-90 seconds Ve: (o mls) + (2.50.mls²)(15.90 s). 39.75 m Is Requined: #: ? Equation: Vf = Vi + a At. b) How long did it take the frain to finish the trip from one station to the other ?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Displacement, Velocity and Acceleration

In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.

Linear Displacement

The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.

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Question

2.) A subway train starts from rest at a station and accelerates at a
rate of 2.50 mls for 15.9b seconds. H then runs at a constant specd of
35 seconds and then slows down at a rate of 4.50 ml s² until it sto ps at
the next station?
Q) what is the speed of the frain to finish tħ before It starts slo wing
down?
Given:
Solution:
Vi: o mis
a: 2.50 m Is²
At:15.90 seconds.
Vp: (o mls) + (2.50 mls²)( 15.90 s)
:
39.75 mls
Requined:
Equation:
Vf = Vi t a At
%3D
b.) How long did it take the train to finish the trip from one station
to the other ?
Given:
Vf= 39.75 mls
t1= 15.90 s
solution
0: 39.75 mls - 4.50 ml S*ts
: 4.50 m Is² to=89.75 mls =
to: 39.75 m ls
4.50 mlsz
: 8.83s
Requinud:
Total time (t)
t: s t 8.83 s
15.90s 35S
59.73s
Equation:
t: tit tz t t3
to: Vf.

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