A horizontal steel girder has a span of 3 m and is built-in at the left-hand end and freely supported at 4 the other end. It carries a uniformly distributed load of 30 kN/m over the whole span, together with a single concentrated load of 20 kN at a point 2 m from the left-hand end. The supporting conditions are such that the reaction at the left-hand end is 65 kN. (a) Determine the bending moment at the left-hand end and draw the B.M. diagram. (b) Give the value of the maximum bending moment. (c) If the girder is 200 mm deep and has a second moment of area of 40 x 10- m* determine the maximum stress resulting from bending [L.Mech E.] [40 kNm; 100 MN/m².]
A horizontal steel girder has a span of 3 m and is built-in at the left-hand end and freely supported at 4 the other end. It carries a uniformly distributed load of 30 kN/m over the whole span, together with a single concentrated load of 20 kN at a point 2 m from the left-hand end. The supporting conditions are such that the reaction at the left-hand end is 65 kN. (a) Determine the bending moment at the left-hand end and draw the B.M. diagram. (b) Give the value of the maximum bending moment. (c) If the girder is 200 mm deep and has a second moment of area of 40 x 10- m* determine the maximum stress resulting from bending [L.Mech E.] [40 kNm; 100 MN/m².]
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![A horizontal steel girder has a span of 3 m and is built-in at the left-hand end and freely supported at
4
the other end. It carries a uniformly distributed load of 30 kN/m over the whole span, together with a single
concentrated load of 20 kN at a point 2 m from the left-hand end. The supporting conditions are such that the
reaction at the left-hand end is 65 kN.
(a) Determine the bending moment at the left-hand end and draw the B.M. diagram.
(b) Give the value of the maximum bending moment.
(c) If the girder is 200 mm deep and has a second moment of area of 40 x 10-“ m* determine the maximum stress
resulting from bending
[LMech. E.] [40 kN m; 100 MN/m'.]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78aee9f8-8add-4a38-8533-4de57d5489b8%2F95b3d163-4206-49fe-9ddc-c4ea9e7e54ab%2F3av8bvr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A horizontal steel girder has a span of 3 m and is built-in at the left-hand end and freely supported at
4
the other end. It carries a uniformly distributed load of 30 kN/m over the whole span, together with a single
concentrated load of 20 kN at a point 2 m from the left-hand end. The supporting conditions are such that the
reaction at the left-hand end is 65 kN.
(a) Determine the bending moment at the left-hand end and draw the B.M. diagram.
(b) Give the value of the maximum bending moment.
(c) If the girder is 200 mm deep and has a second moment of area of 40 x 10-“ m* determine the maximum stress
resulting from bending
[LMech. E.] [40 kN m; 100 MN/m'.]
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