A homozygous mother has retinoblastoma, a dominant sex-linked disorder carried on the X chromosome. The father does not have this disorder. What is the chance they will have a child with this disorder? 1) 0% 2) 25% 3) 50% 4) 75% 5) 100%

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### Inheritance of Retinoblastoma (Dominant X-linked Disorder)

**Question:**
A homozygous mother has retinoblastoma, a dominant sex-linked disorder carried on the X chromosome. The father does not have this disorder. What is the chance they will have a child with this disorder?

**Options:**
1. 0%
2. 25%
3. 50% **(Selected Answer)**
4. 75%
5. 100%

#### Explanation:

Retinoblastoma is a condition that is passed on through the X chromosome. Since it is a dominant disorder, only one copy of the defective gene is needed for an individual to exhibit the disorder.

Given that the mother is homozygous for the disorder, she carries two copies of the defective gene (X^R X^R). The father does not have the disorder and therefore carries the normal gene on his X chromosome (X^r Y).

During reproduction, the mother can only pass on the defective X chromosome to her children (X^R), while the father can pass either his normal X chromosome (X^r) to daughters or his Y chromosome (Y) to sons.

- **Daughters (XX):**
  - Inherit X^R from mother (always)
  - Inherit X^r from father (always)

  Outcome: X^R X^r → All daughters will have retinoblastoma.

- **Sons (XY):**
  - Inherit X^R from mother (always)
  - Inherit Y from father (always)

  Outcome: X^R Y → All sons will have retinoblastoma.

Therefore, regardless of the gender of the child, each child has a 100% chance of inheriting the disorder.

Making an educated guess from the given options, although 100% would be the correct answer in a detailed genetic explanation, the text provides "50%" (option 3) as the selected answer which may indicate incomplete understanding or an error in the given options. Depending on the educational level, further review might be needed for accuracy.
Transcribed Image Text:### Inheritance of Retinoblastoma (Dominant X-linked Disorder) **Question:** A homozygous mother has retinoblastoma, a dominant sex-linked disorder carried on the X chromosome. The father does not have this disorder. What is the chance they will have a child with this disorder? **Options:** 1. 0% 2. 25% 3. 50% **(Selected Answer)** 4. 75% 5. 100% #### Explanation: Retinoblastoma is a condition that is passed on through the X chromosome. Since it is a dominant disorder, only one copy of the defective gene is needed for an individual to exhibit the disorder. Given that the mother is homozygous for the disorder, she carries two copies of the defective gene (X^R X^R). The father does not have the disorder and therefore carries the normal gene on his X chromosome (X^r Y). During reproduction, the mother can only pass on the defective X chromosome to her children (X^R), while the father can pass either his normal X chromosome (X^r) to daughters or his Y chromosome (Y) to sons. - **Daughters (XX):** - Inherit X^R from mother (always) - Inherit X^r from father (always) Outcome: X^R X^r → All daughters will have retinoblastoma. - **Sons (XY):** - Inherit X^R from mother (always) - Inherit Y from father (always) Outcome: X^R Y → All sons will have retinoblastoma. Therefore, regardless of the gender of the child, each child has a 100% chance of inheriting the disorder. Making an educated guess from the given options, although 100% would be the correct answer in a detailed genetic explanation, the text provides "50%" (option 3) as the selected answer which may indicate incomplete understanding or an error in the given options. Depending on the educational level, further review might be needed for accuracy.
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