A hiker walks 50 m East, then 200 m South and finally 400 m West. What is the resultant displacement of the hiker from the starting point? Scale: 1 cm = 50 m 2. A STEM student walks 600 m East, then turns 400 m North and finally walks 300 m West. What is his resultant displacement? Scale: 1 cm = 100 m
A hiker walks 50 m East, then 200 m South and finally 400 m West. What is the resultant displacement of the hiker from the starting point? Scale: 1 cm = 50 m 2. A STEM student walks 600 m East, then turns 400 m North and finally walks 300 m West. What is his resultant displacement? Scale: 1 cm = 100 m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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add the vectors GRAPHICALLY and please show your work with encoded solutions. Just answer given 1 and 2 and follow the other images for the format of answers
- A hiker walks 50 m East, then 200 m South and finally 400 m West.
What is the resultant displacement of the hiker from the starting point?
Scale: 1 cm = 50 m
2. A STEM student walks 600 m East, then turns 400 m North and finally walks 300 m West. What is his resultant displacement?
Scale: 1 cm = 100 m
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a
As, displacement is the shortest distance or can say the distance of the line joining the initial and final point Shift
the object.
b
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PrtScn
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Thus, AC is the displacement of the car and it can be calculated by using the Pythagoras' theorem,
So,
(AC)? = (AB)² + (BC)²
Substituting the values in above equation,
x? = (10)² + (20)²
Solving for x,
x²=100 + 400
x²=500
x=V
:V500
x=22. 36 kmn
Answer: 1) Total displacement of the car is 22.36 km](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a54982e-0c97-462c-b022-56dccb176771%2F41eeb1e3-7d74-4f50-809b-bbf990892b7f%2Fqcwz83_processed.png&w=3840&q=75)
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F1 F2 F3 F4 F5 F6 F7 F8 F9
F10 F11 F12
Home
PgUp
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Step 3
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t
i
Del
End
PgDn
Mv Up
w
e
r
y
u
[
Сaps
d f
h j
Enter
Insert
Pause
Mv Dn
a
As, displacement is the shortest distance or can say the distance of the line joining the initial and final point Shift
the object.
b
Shift
PrtScn
ScrLk
Dock
V
n
En Ctrl
H Alt
Alt
Ctrl
Options
Help
Fade
Thus, AC is the displacement of the car and it can be calculated by using the Pythagoras' theorem,
So,
(AC)? = (AB)² + (BC)²
Substituting the values in above equation,
x? = (10)² + (20)²
Solving for x,
x²=100 + 400
x²=500
x=V
:V500
x=22. 36 kmn
Answer: 1) Total displacement of the car is 22.36 km
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Solution: 1) The situation provided can be drawn graphically as shown below,
Caps
d f
h j
Enter
Insert
Pause
Mv Dn
a
Shift
b
Shift
PrtScn
ScrLk
Dock
V
n
North
Alt
Alt
En Ctrl
Ctrl
Options
Help
Fade
20 km
C
10 km
West e
А
East
South
Here, A is the initial point of the car and C is the final point of the car.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a54982e-0c97-462c-b022-56dccb176771%2F41eeb1e3-7d74-4f50-809b-bbf990892b7f%2Frp7qe3q_processed.png&w=3840&q=75)
Transcribed Image Text:= bartleby
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F1 F2 F3 F4 F5 F6 F7 F8 F9
F10 F11 F12
Home
PgUp
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Tab
t
i
Del
End
PgDn
Mv Up
w
e
r
y
u
[
Solution: 1) The situation provided can be drawn graphically as shown below,
Caps
d f
h j
Enter
Insert
Pause
Mv Dn
a
Shift
b
Shift
PrtScn
ScrLk
Dock
V
n
North
Alt
Alt
En Ctrl
Ctrl
Options
Help
Fade
20 km
C
10 km
West e
А
East
South
Here, A is the initial point of the car and C is the final point of the car.
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