(a) highest boiling point O HBr Br2 O Ne Since this compound has dipole-dipole forces E unlike the other two compounds, it has the strongest intermolecular forces and will have the highest boiling point. (b) highest freezing point O H20 Ο ΝH3 O NaBr Since this compound has -Select- D unlike the other two compounds, it has the --Select--- intermolecular forces and will have the highest freezing point. (c) lowest vapor pressure at 25°C O Cl2 O I2 O F2 Since all the molecules are -Select-- and this molecule is -Select--- than the other two, it has the -Select--- --Select-- and will have the lowest vapor pressure. (d) lowest freezing point O H2S CSe2 O 02 Since this molecule is and -Select- than the other two, it has the --Select--- ---Select--- ---Select-- - and will have the lowest freezing point. (e) lowest boiling point O CH3CH2CH3 O CH3CH,CH,CH3 O CH2CH2 Since this molecule is -Select-- and -Select- than the other two, it has the ---Select-- E and will have the lowest boiling point. -Select-- (1) highest boiling point HCI о Her O HF Since this compound has -Select-- - unlike the other two compounds, it has the -Select--- intermolecular forces and will have the highest boiling point. (9) lowest vapor pressure at 25°C O CH3CH2CH2CH3 O CH3CH20CH2CH3 O CH3CH,CH,CH2OH Since this compound has -Select--- unlike the other two compounds, it has the Select-- intermolecular forces and will have the lowest vapor pressure.
(a) highest boiling point O HBr Br2 O Ne Since this compound has dipole-dipole forces E unlike the other two compounds, it has the strongest intermolecular forces and will have the highest boiling point. (b) highest freezing point O H20 Ο ΝH3 O NaBr Since this compound has -Select- D unlike the other two compounds, it has the --Select--- intermolecular forces and will have the highest freezing point. (c) lowest vapor pressure at 25°C O Cl2 O I2 O F2 Since all the molecules are -Select-- and this molecule is -Select--- than the other two, it has the -Select--- --Select-- and will have the lowest vapor pressure. (d) lowest freezing point O H2S CSe2 O 02 Since this molecule is and -Select- than the other two, it has the --Select--- ---Select--- ---Select-- - and will have the lowest freezing point. (e) lowest boiling point O CH3CH2CH3 O CH3CH,CH,CH3 O CH2CH2 Since this molecule is -Select-- and -Select- than the other two, it has the ---Select-- E and will have the lowest boiling point. -Select-- (1) highest boiling point HCI о Her O HF Since this compound has -Select-- - unlike the other two compounds, it has the -Select--- intermolecular forces and will have the highest boiling point. (9) lowest vapor pressure at 25°C O CH3CH2CH2CH3 O CH3CH20CH2CH3 O CH3CH,CH,CH2OH Since this compound has -Select--- unlike the other two compounds, it has the Select-- intermolecular forces and will have the lowest vapor pressure.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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States of Matter
The substance that constitutes everything in the universe is known as matter. Matter comprises atoms which in turn are composed of electrons, protons, and neutrons. Different atoms combine together to give rise to molecules that act as a foundation for all kinds of substances. There are five states of matter based on their energies of attraction, namely solid, liquid, gases, plasma, and BEC (Bose-Einstein condensates).
Chemical Reactions and Equations
When a chemical species is transformed into another chemical species it is said to have undergone a chemical reaction. It consists of breaking existing bonds and forming new bonds by changing the position of electrons. These reactions are best explained using a chemical equation.
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Transcribed Image Text:In each of the following groups of substances, pick the one that has the given
property. Justify your answer.
(a) highest boiling point
о HBr
O Br2
O Ne
Since this compound has dipole-dipole forces
- unlike the other two compounds, it
has the (strongest 7 intermolecular forces and will have the highest boiling point.
(b) highest freezing point
O H20
O NH3
O NaBr
unlike the other two compounds, it
intermolecular forces and will have the highest freezing point.
Since this compound has -Select--
has the --Select---
(c) lowest vapor pressure at 25°C
O Cl2
O I,
O F2
Since all the molecules are
and this molecule is -Select--- than the
Select--
other two, it has the --Select---
--Select--
and will have the lowest
vapor pressure.
(d) lowest freezing point
O H2S
O CSe2
O 02
Since this molecule is
--Select---
and -Select-- than the other two, it has the
--Select--- -Select--
- and will have the lowest freezing point.
(e) lowest boiling point
O CH3CH2CH3
O CH3CH2CH,CH3
O CH2CH2
Since this molecule is --Select-- and -Select-- than the other two, it has the
---Select--
and will have the lowest boiling point.
---Select---
(1) highest boiling point
O HCI
о Her
O HF
Since this compound has -Select--
- unlike the other two compounds, it
has the
intermolecular forces and will have the highest boiling point.
--Select---
(g) lowest vapor pressure at 25°C
O CH3CH2CH2CH3
O CH3CH2OCH,CH3
O CH3CH2CH,CH2OH
Since this compound has -Select--
has the
unlike the other two compounds, it
--Select--- intermolecular forces and will have the lowest vapor pressure.
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