A high-speed photograph of a club hitting a golf ball is shown in the figure below. The club was in contact with a ball, initially at rest, for about 0.0029 s. If the ball has a mass of 55 g and leaves the head of the club with a speed of 2.5 x 10 ft/s, find the average force (in kN) exerted on the ball by the club. kN

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Chapter1: Units, Trigonometry. And Vectors
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**High-Speed Photograph of a Golf Club Hitting a Ball**

A high-speed photograph of a club hitting a golf ball is shown in the figure above. The image captures the moment of impact between the club and the ball, illustrating the dynamics of motion.

**Scenario Description:**

The club was in contact with the ball, initially at rest, for about \(0.0029 \, \text{s}\). If the ball has a mass of \(55 \, \text{g}\) and leaves the head of the club with a speed of \(2.5 \times 10^2 \, \text{ft/s}\), find the average force (in \(\text{kN}\)) exerted on the ball by the club.

**Calculation:**
- Mass of the ball (\(m\)): \(55 \, \text{g}\)
- Speed of the ball after impact (\(v\)): \(2.5 \times 10^2 \, \text{ft/s}\)
- Time of contact (\(t\)): \(0.0029 \, \text{s}\)

\[
\text{Average force (F)} = \frac{m \times v}{t}
\]

**Note:** The formula above assumes conversion of units where necessary. Calculate to find the force in kilonewtons (kN).

**Input Field:**
- [ __ ] kN
Transcribed Image Text:**High-Speed Photograph of a Golf Club Hitting a Ball** A high-speed photograph of a club hitting a golf ball is shown in the figure above. The image captures the moment of impact between the club and the ball, illustrating the dynamics of motion. **Scenario Description:** The club was in contact with the ball, initially at rest, for about \(0.0029 \, \text{s}\). If the ball has a mass of \(55 \, \text{g}\) and leaves the head of the club with a speed of \(2.5 \times 10^2 \, \text{ft/s}\), find the average force (in \(\text{kN}\)) exerted on the ball by the club. **Calculation:** - Mass of the ball (\(m\)): \(55 \, \text{g}\) - Speed of the ball after impact (\(v\)): \(2.5 \times 10^2 \, \text{ft/s}\) - Time of contact (\(t\)): \(0.0029 \, \text{s}\) \[ \text{Average force (F)} = \frac{m \times v}{t} \] **Note:** The formula above assumes conversion of units where necessary. Calculate to find the force in kilonewtons (kN). **Input Field:** - [ __ ] kN
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