A herbicide contains 2,4-D (2,4-dichlorophenoxyacetic acid), C8 H6 Cl2 O3. A 1.265-g sample of the herbicide was decomposed to liberate the chlorine as CI ion. This was precipitated as AgCl, with a mass of 0.1410 g. What is the mass percent of 2,4-D in the sample? OCH₂CO₂H H. Mass percent H C C C CL 2,4-D (2,4-dichlorophenoxyacetic acid). H %

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**Determining the Mass Percent of 2,4-D in a Herbicide Sample**

**Problem Statement:**
A herbicide contains 2,4-D (2,4-dichlorophenoxyacetic acid), \(C_8H_6Cl_2O_3\). A 1.265-g sample of the herbicide was decomposed to liberate the chlorine as \(Cl^-\) ion. This was precipitated as \(AgCl\), with a mass of 0.1410 g. What is the mass percent of 2,4-D in the sample?

**Chemical Structure:**

[Graphic of chemical structure for 2,4-D]

![](https://res.cloudinary.com/path-to-your-image.jpg)
   - The structure shows a benzene ring with the following groups attached: two chlorine atoms (at positions 2 and 4), a methylene bridge, and an acetic acid functional group.

**Calculation Steps:**

1. **Determine the amount of \(Cl^-\) from \(AgCl\):**
   - Molar mass of \(AgCl\): 
     * Ag = 107.87 g/mol
     * Cl = 35.45 g/mol
     * \(107.87 + 35.45 = 143.32 \) g/mol
   - Moles of \(AgCl\):
     \[
     \text{Moles of } AgCl = \frac{0.1410 \text{ g}}{143.32 \text{ g/mol}} = 9.84 \times 10^{-4} \text{ mol}
     \]

2. **Convert moles of \(AgCl\) to moles of \(Cl^-\):**
   - Each mole of \(AgCl\) contains 1 mole of \(Cl^-\), so:
     \[
     \text{Moles of } Cl^- = 9.84 \times 10^{-4} \text{ mol}
     \]

3. **Mass of \(Cl^-\):**
   - Molar mass of Cl = 35.45 g/mol
   \[
   \text{Mass of } Cl^- = 9.84 \times 10^{-4} \text{ mol} \times 35.45 \text{ g/mol} = 0.03488 \text{ g}
   \]

4. **
Transcribed Image Text:**Determining the Mass Percent of 2,4-D in a Herbicide Sample** **Problem Statement:** A herbicide contains 2,4-D (2,4-dichlorophenoxyacetic acid), \(C_8H_6Cl_2O_3\). A 1.265-g sample of the herbicide was decomposed to liberate the chlorine as \(Cl^-\) ion. This was precipitated as \(AgCl\), with a mass of 0.1410 g. What is the mass percent of 2,4-D in the sample? **Chemical Structure:** [Graphic of chemical structure for 2,4-D] ![](https://res.cloudinary.com/path-to-your-image.jpg) - The structure shows a benzene ring with the following groups attached: two chlorine atoms (at positions 2 and 4), a methylene bridge, and an acetic acid functional group. **Calculation Steps:** 1. **Determine the amount of \(Cl^-\) from \(AgCl\):** - Molar mass of \(AgCl\): * Ag = 107.87 g/mol * Cl = 35.45 g/mol * \(107.87 + 35.45 = 143.32 \) g/mol - Moles of \(AgCl\): \[ \text{Moles of } AgCl = \frac{0.1410 \text{ g}}{143.32 \text{ g/mol}} = 9.84 \times 10^{-4} \text{ mol} \] 2. **Convert moles of \(AgCl\) to moles of \(Cl^-\):** - Each mole of \(AgCl\) contains 1 mole of \(Cl^-\), so: \[ \text{Moles of } Cl^- = 9.84 \times 10^{-4} \text{ mol} \] 3. **Mass of \(Cl^-\):** - Molar mass of Cl = 35.45 g/mol \[ \text{Mass of } Cl^- = 9.84 \times 10^{-4} \text{ mol} \times 35.45 \text{ g/mol} = 0.03488 \text{ g} \] 4. **
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