Consider the reaction: Cu2+(aq) + 4NH3(aq) 2 Cu(NH3)4²*(aq) Kf= 1.7x 1013 What is [Cu2*] remaining in solution after 0.020 mol of CuSO4 is dissolved in 1.00 L of 0.70 M NH3? Assume no change of volume. 3.8 x 10-14 M 1.6 x 10-14 M 1.1 x 10-13 M 8.0 x 10-15 M 5.0 x 10-13 M O O O O O

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Q: Consider the following equilibrium: Cu²+ (aq) + 4NH3(aq) Cu(NH3)4²+ (aq) (Kf = 4.8e+12) A solution…

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