A helical compression spring shown in figure, experience a minimum force of 150 1b at just before ignition. During the working cycle it experiences addition force as it is compressed by an inch. The spring rate is 50 lb/in. The coil must fit in a 2.1-in-dia hole with 0.1 in clearance. Use 0.25 in diameter, peened, OQ&T wire and squared/ground ends. Find a) The stresses and safety factor for infinite life fatigue. b) Calculate the number of the coils. (Shear modulus G=11.5 x10^6 psi) Note that for peened springs, Zimmerli's finding is updated as follows: Ssa = 57.5 kpsi (398 MPa) and Ssm = 77.5 kpsi (534 MPa)

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A helical compression spring is required to provide a minimum force of 150 lb at installation and have a working deflection of 1 in. The spring rate is 75 lb/in. The coil must fit in a 2.1-in-dia hole with 0.1 in total clearance. Use 0.25-in diameter unpeened music wire and squared/ground ends. Use a 15% clash allowance, shear modulus G = 11.5 Mpsi, and weight density γ = 0.285 lb/in3. Assume Sys = 0.6Sut. Part A Find the shear stress at the initial deflection. Express your answer in pounds per square inch to three significant figures.         τiτi =       Part B Find the mean stress. Express your answer in pounds per square inch to three significant figures.     Part C Find the alternating stress in the coil. Express your answer in pounds per square inch to three significant figures.     Part D Find the fatigue safety factor for infinite life in shear. Express your answer using three significant figures.…

A helical compression spring is made with oil-tempered wire of diameter 0.2", mean coil diameter of 2", 12 total coils, 5" free length, and squared ends. (a) Find the solid length. (b) Find the force required to compress the spring to closure? (c) Find the factor of safety against yield when compressed to the solid length. (Hint: Uses Say= 0.5 Sut for shear strength.)