A has $6,750 available per month for advertising. Newspaper ads cost $160 each and can't run company more than 24 times per month. Radio ads cost $430 each and can't run more than 33 times per month at this price. Each newspaper ad reaches 6800 potential customers, and each radio ad reaches 8250 potential customers. The company wants to maximize the number of ad exposures to potential customers. Use n for number of Newspaper advertisements and r for number of Radio advertisements . Maximize P = subject to < 24 < 33 < $6, 750 Enter the solution below. If needed, round ads to 1 decimal palace and group exposure to the nearest whole person. Number of Newspaper ads to run is Number of Radio ads to run is Maximum target group exposure is people
Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 miles away.
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experiments to set up the devices.
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