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A hair dryer is mainly a duct in which layers of electrical resistors are placed. A small fan pulls in air from outside and forces it past the resistors, where it is heated. Air at 100 kPa and 27°C enters a 1500 W hair dryer and leaves at 80°C. The cross-sectional area of the dryer at the outlet is 75 cm^2. Neglect the power consumed by the fan and the thermal losses through the walls of the dryer. Plot the control volume, determine the volumetric flow of air at the inlet, and calculate the velocity of the air at the outlet.

A hair dryer is mainly a duct in which layers of electrical resistors are placed. A small fan pulls in air from outside and forces it past the resistors, where it is heated. Air at 100 kPa and 27°C enters a 1500 W hair dryer and leaves at 80°C. The cross-sectional area of the dryer at the outlet is 75 cm^2. Neglect the power consumed by the fan and the thermal losses through the walls of the dryer. Plot the control volume, determine the volumetric flow of air at the inlet, and calculate the velocity of the air at the outlet.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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P24. A hair dryer is mainly a duct in which layers of electrical resistors are placed. A small fan pulls in air from outside and forces it past the resistors, where it is heated. Air at 100 kPa and 27°C enters a 1500 W hair dryer and leaves at 80°C. The cross-sectional area of the dryer at the outlet is 75 cm^2.
Neglect the power consumed by the fan and the thermal losses through the walls of the dryer. Plot the control volume, determine the volumetric flow of air at the inlet, and calculate the velocity of the air at the outlet.

T₂ = 80 °C V₂ = 21 m/s P₁ = 100 kPa T₁ = 300 K
Transcribed Image Text:T₂ = 80 °C V₂ = 21 m/s P₁ = 100 kPa T₁ = 300 K
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