A group of researchers wanted to estimate the proportion of people with type 2 diabetes worldwide. In a random sample of 500 people, 8% have type 2 diabetes. 1. Check if the conditions for one-sample z-interval for population proportion is satisfied 2. If satisfied, compute for the 90% confidence interval for the population proportion.
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- Suppose an insurance company randomly surveyed 633 drivers and found that 601 claimed they always buckled up. Construct a 94% confidence interval for the fraction of all drivers who buckle up. p' = NR dje = Margin of Error: E = We are 94% confident that the fraction of drivers who always buckle up is between andA random sample of n1 278 people who live in a city were selected and 98 identified as a "dog person." A random sample of n2 = 109 people who live in a rural area were selected and 65 identified as a "dog person." Find the 90% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < pi – p2 < Submit QuestionA researcher wants to compare the effectiveness of two different study techniques for a test. The mean test score for the first technique is 75 with a standard deviation of 5, and the mean test score for the second technique is 80 with a standard deviation of 4. The sample size for each group is 20. What is the 95% Confidence Interval for the difference in the mean test scores for the two techniques?
- A random sample of 500 males included 215 that approved of the performance of a President. A random sample of 500 females included 185 that approved of the performance of a President. Determine each of the following parts that will lead you to construct a 95% confidence interval for the overall difference in the percentage of males and females that approve of the President's performance. group one males, gorup 2 females Calculate E, the margin of error, for a 95% level of confidence, Create the final confidence interval for the difference in percentagesA flower shop owner wants to estimate the proportion of people who enter the store that make a purchase. They want a 95% confidence interval on the proportion of people who enter the store that make a purchase with a margin for error of 0.04 or 4%. Their partner estimates that 20% (a proportion of 0.2) of the people who enter the store make a purchase so the owner will use that value when determining the sample size. What sample size should the flower shop take?Construct a 95% confidence interval of the population proportion using the given information. x=80 n= 200 Give lower and upper bound
- Suppose that the population standard deviation of a student's score is 20. Choose a sample size so that the resulting 95% confidence interval for the population mean score has a margin of error no larger than 5.It is estimated that in the general population about 9 out of every 1000 or 0.009 children are diagnosed with autism. on study included 92 six month old babies who had a sibling with autism. twenty-eight of these babies were later diagnosed with autism. we will systematically construct a 99% confidence interval for the proportion of siblings of autistic children likely to have autism. What is the population being studied? What population parameter are we seeking to estimate? Describe this population parameter in words.A researcher surveys a group of college students to determine the negative life events that they experienced in the past 5 years and their current feeling of well-being. For N = 18 participants with 2 or fewer negative experiences, the average well-being score was X = 42 with SS = 398. For the N = 16 participants with 5 to 10 negative experiences the average score is X = 48.6 with SS = 370. Construct a 95% confidence interval for the difference between the population means for the two groups.
- One scientist wondered if there was a difference in the average daily intake of dairy products between men and women. He took a sample of n1 = 50 adult men and n2 = 50 adult women and recorded their daily intake of dairy products in grams per day. A summary of the sample results is presented in the table. Construct a 95% confidence interval for the difference in the average daily intake of dairy products for men and women. Can it be concluded that there is a difference in the average daily intakes for men and women?A large p-value indicates that the data is consistent with the alternative hypothesis. True or false?Apply the t-interval procedure to find a 95% confidence interval for the mean arterial blood pressure of 8 children sampled if x=85.99 mm Hg and s=8.08 mm Hg