**Question:**A gold wire of 0.500 mm diameter has \(8.20 \times 10^{28}\) conduction electrons per cubic meter. If the drift speed is \(6.30 \, \mu\text{m/s}\), what is the current in the wire?[ ] mA**Explanation:**Given:- Diameter of the wire = 0.500 mm- Conduction electrons = \(8.20 \times 10^{28}\) electrons/m\(^3\)- Drift speed = \(6.30 \, \mu\text{m/s}\)To calculate the current in the wire, use the formula:\[ I = n \cdot A \cdot v_d \cdot e \]Where:- \(I\) is the current in amperes.- \(n\) is the conduction electron density.- \(A\) is the cross-sectional area of the wire.- \(v_d\) is the drift speed.- \(e\) is the charge of an electron (\(1.6 \times 10^{-19}\) C).Steps:1. Calculate the cross-sectional area \(A\) of the wire: \[ A = \pi \left( \frac{\text{Diameter}}{2} \right)^2 \]2. Convert diameter from mm to meters and drift speed from \(\mu\text{m/s}\) to \(\text{m/s}\).3. Substitute the values into the formula to find the current \(I\).Finally, convert the current from amperes to milliamperes (mA) if necessary by multiplying by 1000.

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Answered: A gold wire of 0.500 mm diameter has…

A gold wire of 0.500 mm diameter has 8.20 × 1028 conduction electrons per cubic meter. If the drift speed is 6.30 um/s, what is the current in the wire? |mA

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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