A gold cathode (work function = 5.1 eV) is illuminated with light of wavelength 250 nm. It is found that the photoelectron current is zero when AV= 0 V. Would the current change if: a. The intensity is doubled? b. The anode-cathode potential difference is increased to AV = 5.5 V? c. The cathode is changed to aluminum (work function = 4.3 eV)? %3D
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- Help with a iv, b and cCan you explain this to me? Needs Complete solution with 100 % accuracy.A. The binding energy of Sodium is 2.28 eV. Calculate the number of photoelectrons ejected from a 1.00 mm2 area of Sodium metal by 500-nm electromagnetic radiation having an intensity of 1.30 kW/m2. What power is carried away by the electrons? B. Suppose that 0.1 kg of ice at an initial temperature of -10°C are put into 0.40kg of water at an initial temperature of 20°C. Assume the final temperature is 0°C. How many grams of ice will melt? Specific heat capacity of water is 4,200 J/kg/°C. Specific heat of fusion of water is 336,000 J/kg and specific heat capacity of ice is 2,100 J/kg/°C.
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