A glass rod is given positive charge by rubbing it against silk. The glass rod is then rubbed against a metal slab (on an insulating stand), transferring the positive charge on the rod to the slab. Which of the following statements is true concerning the electric field at a point just outside the upper surface of the slab? It is zero because the electric field is always zero for isolated conductors. It is parallel to the surface. It is perpendicular to the surface. It can have nonzero components perpendicular to and parallel to the surface of the conductor. None of these

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A glass rod is given positive charge by rubbing it against silk. The glass rod is then
rubbed against a metal slab (on an insulating stand), transferring the positive charge
on the rod to the slab. Which of the following statements is true concerning the
electric field at a point just outside the upper surface of the slab?
It is zero because the electric field is always zero for isolated conductors.
It is parallel to the surface.
It is perpendicular to the surface.
It can have nonzero components perpendicular to and parallel to the surface of
the conductor.
None of these
It is zero because the electric fields of the positive charges will be cancelled out by the
electric fields of the electrons.
Transcribed Image Text:A glass rod is given positive charge by rubbing it against silk. The glass rod is then rubbed against a metal slab (on an insulating stand), transferring the positive charge on the rod to the slab. Which of the following statements is true concerning the electric field at a point just outside the upper surface of the slab? It is zero because the electric field is always zero for isolated conductors. It is parallel to the surface. It is perpendicular to the surface. It can have nonzero components perpendicular to and parallel to the surface of the conductor. None of these It is zero because the electric fields of the positive charges will be cancelled out by the electric fields of the electrons.
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Physics homework question answer, step 1, image 1

Just after charge is transfered it will start to spread out on the surface and the component of electric fields that are parrallel to surface will move the charges till the parrallel components cancel out and charges are spread out evenly and equlibrium is attained.

 

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