A glass containewas initially charged with 2.00 moles of a gas sample at 3.75 atm and 21.7°C. Some of the gas was released as the temperature was increased to 28.1°C, so the final pressure in the container was reduced to 0.998 atm. What quantity in moles of the gas sample are present at the end?

Q: If 2.84 g Ar are added to 2.08 atm He in a 2.00 L cylinder at 27.0 °C, what is the total pressure of…

A: P( He) = 2.08 atm Using , ideal gas equation PV= nRT , we can calculate the pressure of Ar gas…

Q: Xenon fluoride can be prepared by heating a mixture of Xe and F2 gases to a high temperature in a…

A: That formula that give an idea of the relative atomic ratios of the compound is called empirical…

Q: A 1.59 g sample of a silicon-fluorine compound is determined to be 26.99% silicon by mass at 27.0…

A: m=RT/PV = ((2.60)(.0821)(300))/((1.50)(.250)) = 170.7 Mol wt=170.7 33.01 %Si -100 = 66.99%F 33.01g…

Q: If 1.04 g Ar are added to 4.83 atm He in a 2.00 L cylinder at 27.0 °C, what is the total pressure of…

A: We have to calculate the total gas pressure of mixture.

Q: A mixture containing 0.765 mol He(g), 0.330 mol Ne(g),and 0.110 mol Ar(g) is confined in a 10.00-L…

A:

Q: A mixture of methane and neon gases, in a 5.79 L flask at 55 °C, contains 4.14 grams of methane and…

A: Given  Volume ( V ) = 5.79 Liter  Temperature ( T )  = 55 ℃                               = ( 55 +…

Q: A mixture of oxygen and carbon dioxide gases contains oxygen at a partial pressure of 583 mm Hg and…

A: The mole fraction of oxygen and carbon dioxide is calculated as,

Q: 9. An unknown gas was analyzed, and the following data was obtained. Mass of the gas sample 1.211 g…

A: The ideal gas equation says that PV - nRT where, P = pressure, V = volume, n=number of moles , R=…

Q: If 3.75 g Ar are added to 4.26 atm He in a 2.00 L cylinder at 27.0 °C, what is the total pressure of…

A: Given mass of argon = 3.75 g Molar mass of argon = 39.95 g/mol Number of moles of argon (n) =…

Q: The gaseous composition of exhaled breath of air by number analysis of the number of moles is 74.8%…

A: Answer:- This question is answered by using the simple concept of Daltons's partial pressure law…

Q: A gaseous mixture containing 7 moles of nitrogen, 2.5 moles of oxygen and 0.50 mole of helium exerts…

A: Concept: Partial Pressure: it can be define as if a container filled with more than one gas, each…

Q: Container A holds 762 mL762 mL of an ideal gas at 2.30 atm.2.30 atm. Container B holds 159 mL159 mL…

A: By using Daltons law we can find total resulting pressure of Mixing.

Q: A flask contains a mixture of 2.20 g of CO2 gas and 4.80 g of O2 gas, at a total pressure of 1.00…

A: A flask contains a mixture of 2.20 g of CO2 gas and 4.80 g of O2 gas, at a total pressure of 1.00…

Q: A sample of methane gas at a pressure of 735 mm Hg and a temperature of 76 °C, occupies a volume of…

A: According to the question given are, Pressure = 735 mm Hg ( constant through the process)T1 = 76°C =…

Q: mixture of unreacted gas which consists of 21 g of nitrogen gas and 6 g of hydrogen gas is placed in…

A:

Q: 2.9 g of N2 are mixed with 2.59 atm of H2 in a 772 mL container at 298 K. If 0.21 g of NH3 are…

A: Given, Amount of N2 reacts 2.9 g Pressure of H2 = 2.59 atm Volume of H2 = 772 ml = 0.772 L…

Q: A sample of hydrogen gas at a pressure of 995 mm Hg and a temperature of 30.°C, occupies a volume of…

A: We can solve the problem by the formula  PV = nRT   Where  P = pressure of the gas (in atm) V =…

Q: A 4.00 L flask filled with He at 6.00 atm is connected to another 2.00 L flask containing N2 at 3.00…

A: Considered that the temperature of the system is 298.15 K. The number of moles of He and N2 is…

Q: The mass percent of a three component gas sample is 40.8% B4H8, 14.4% C2H4O2 and 44.8% C2H4F2.…

A: Dalton’s Law of Partial Pressures states that the total pressure exerted by the mixture of…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.