A girl and a boy each exert a force to move acrate horizontally a distance of 13m at aconstant speed. The girl's applied forced is75N [22° below the horizontal]. The tensionin the rope pulled by the boy is 75N [32°above the horizontal]. Determine the workdone by the boy and the girl. Determine the force of friction and the work doneby friction. If the coefficient of kinetic friction between the box and the floor is0.5, what is the mass of the crate?Answer: WgirlFil As = (75cos 22° N)(13m) -9.04×10°JFroy As = (75cos 32°N)(13m) 8.27x10² JW boyboy.xConstant speed means a= 0, which means net work done is also zero.As a result, W, =-(9.04x10² +8.27×10°)J=-1.73×10'J.W, = F,As=F, -133N. F = µF→Fy 266N .F =mg -72sin 22° -75 sin 32° m 34kgSource: modified from Nelson, Physics 12, 2002, p.183, Section 4.1, #5

Solution:-Given thatdisplacement (d)=13 mμ=0.5

Answered: A girl and a boy each exert a force to…

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