A force F = bx pushes a 2.0-kg box initially at rest at r = 0 up the smooth frictionless surface of an incline.The angle of the incline is 0 = 30° and b is a constant which has the value 3.0 N/m3. Calculate Wforce, the workdone by this force, Wgrav, the work done by gravity, and the final speed of the block, vf, when the box is pushed|3Dup to x = 4.0 m.(A) Wforce = 192 J, Wgrav39.2 J and vf = 15.2 m/s(B) Wforce = 192 J, Wgrav = -39.2 J and vf = 12.4 m/s%3D%3D(C) Wforce = 192 J, Wgrav = -39.2 J and vf = 15.2 m/s%3D4.0 m(D) Wforce48 J, Wgrav = 39.2 J and vf =%3D9.3 m/s(E) Wforce = 48 J, Wgrav = -39.2 J and vf9.3 m/s(F) Wforce = 48 J, Wgrav =%3D39.2 J and vf = 12.4 m/sF(x)A block being INished up an incline by aposition-dependent force.

Name: A force F = bx pushes a 2.0-kg box initially at rest at r = 0 up the
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: A force F = bx pushes a 2.0-kg box initially at rest at r = 0 up the smooth frictionless surface of an incline.The angle of the incline is 0 = 30° and b is a constant which has the value 3.0 N/m3. Calculate Wforce, the workdone by this force, Wgrav,

Work done by the force Wforce=∫x1x2Fdx=∫04.00 mbx3dx=bx4404.00 m=3.0 Nm34.00 m44=192 J

Science

Physics

A force F The angle of the incline is 0 = 30° and b is a constant which has the value 3.0 N/m3. Calculate Wforce, the work done by this force, Wgrav, the work done by gravity, and the final speed of the block, vs. when the box is pushed br pushes a 2.0-kg box initially at rest at r 0 up the smooth frictionless surface of an incline. up to x = 4.0 m. %3D (A) Wforce = 192 J, Wgrav = 39.2 J and vf = 15.2 m/s %3D (B) Wforce = 192 J, Wgrav - -39.2 J and vf = 12.4 m/s (C) Wforce = 192 J, Wgrav = -39.2 J and vf = 15.2 m/s %3D %3D 4.0 m (D) Wforce = 48 J, Wgrav = 39.2 J and vf = 9.3 m/s (E) Wforce 48 J, Wgrav = -39.2 J and vr %3D 9.3 m/s %3D (F) Wforce = 48 J, Wgrav = 39.2 J and vf = 12.4 m/s F(r) A block being Nıshed up an incline by a noriti

A force F The angle of the incline is 0 = 30° and b is a constant which has the value 3.0 N/m3. Calculate Wforce, the work done by this force, Wgrav, the work done by gravity, and the final speed of the block, vs. when the box is pushed br pushes a 2.0-kg box initially at rest at r 0 up the smooth frictionless surface of an incline. up to x = 4.0 m. %3D (A) Wforce = 192 J, Wgrav = 39.2 J and vf = 15.2 m/s %3D (B) Wforce = 192 J, Wgrav - -39.2 J and vf = 12.4 m/s (C) Wforce = 192 J, Wgrav = -39.2 J and vf = 15.2 m/s %3D %3D 4.0 m (D) Wforce = 48 J, Wgrav = 39.2 J and vf = 9.3 m/s (E) Wforce 48 J, Wgrav = -39.2 J and vr %3D 9.3 m/s %3D (F) Wforce = 48 J, Wgrav = 39.2 J and vf = 12.4 m/s F(r) A block being Nıshed up an incline by a noriti

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Three clowns move a 275 kg crate 10.5 m to the right across a smooth floor. Take the positive…

A: The expression for the work done is as follows: W=F→·d→W=Fdcosθ 1 The expression to…

Q: Work to move car

A: Approach to solving the question:Please see attached photos for detailed solutions. Thank you.…

Q: 1. Emma pushes a 45.0kg box across a level floor with an applied force of 153N [30° above…

A: Work-done by applied Force: W = F.d = F*d*cos theta F_app = applied Force = 155 N d = displacement =…

Q: Which of the following is correct / True? O A. The kinetic energy of a system must always be…

Q: A 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The…

A: Normal reaction is perpendicular to the displacement

Q: A car of mass m = 1200kg travels a distance A, = 2.2 km. At the beginning of the movement the speed…

A: Given that the car of mass m=1200kg moving initially with velocity v0=10m/s covers a distance…

Q: 1.) A force F = 15xi - 5yj, where F is in Newtons and x and y are in meters. a. Find the work done…

Q: A 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The…

A: Given data: Mass (m) = 65.0 kg Distance (d) = 5.00 m Frictional force (f) = 75.0 N g = 10.0 m/s2…

Q: A constant force with a magnitude Facts on an object while the object moves along a straight path a…

Q: A 27-kg box is being moved 16.0 m up a ramp, inclined at 25° from the horizontal. Two forces are…

Q: Needs Complete solution with 100 % accuracy. Don't use chat gpt or ai. Plz plz plz.

A: Step 1: here we have calculate the output power Step 2: here we have calculate the input power Step…

Q: A force of 434.0 N is exerted on a 1,250 N car while moving it a distance of 2.65 m. How much work…

A: Express the relation for the work done on the car. W=Fd Here, W is the work done, F is the force…

Q: 3. A sled of mass 70 kg starts from rest and slides down a 10° incline 70 m long. It then travels…

A: The work done by the system on the sled is W=700.76 J

Q: A block of mass 12kg is being pulled to the right by a rope that makes a 37 degree angle with the…

A: Given data: Mass (m) = 12 kg Angle (θ) = 37° with the horizontal Displacement (d) = 21 m Tension…

Q: WE-2 A 65.0kg crate is initially moving at 5.00m/s up a rough ramp. A horizontal force P-400N pushes…

A: Data:-∙Mass of the crate isM=65.0 kg∙Initial speed of ramp isu=5 m/s∙Hoizontal force…

Q: Calculate Work by Force F applied to mass M=3.0 Kg, producing displacement r. F = 5.1 x + 3.2 y…

A: Given: Force vector, F = 5.1 x i+ 3.2 y j Displacement vector, r = 25x i - 12.3 y j

Q: A 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The…

Q: The force component along the displacement varies with the magnitude of the displacement, as shown…

A: Given: The graph between force and displacement is given.Find: The work done by the force in the…

Q: A sled is pulled for 15 m by a variable force as shown in the figure below. Calculate the work done…

A: The area under the force vs. displacement graph is equal to the amount of work done on the object by…

Q: 3. A certain force applied on an object is depicted below. (a) What is the work done by the force…

Q: A weight W is accelerated from rest by a constant force, F, through a distance d across a…

Q: 3.Starting from the rest and height of 8 m, a 3 kg object slides down a 30° m incline, reaching the…

Q: WE-2 A 65.0kg crate is initially moving at 5.00m/s up a rough ramp. A horizontal force P=400N pushes…

A: Force is an external agent that has the ability to change the state of rest or motion of a certain…

Q: A 65.0-kg file cabinet of is sliding down a rough ramp for a distance of 5.00 m as shown. The…

A: Given data The mass of the file cabinet is given as m = 65 kg. The distance traveled by the cabinet…

Q: A 980 kg car travels a distance of 6.00 m uphill along a road that makes an angle of 30.0∘ with the…

A: Mass of the car m = 980 kg.Distance is given as s = 6 m.Angle is given as Accelration of the car

Topic Video

Question

A force F = bx pushes a 2.0-kg box initially at rest at r = 0 up the smooth frictionless surface of an incline.
The angle of the incline is 0 = 30° and b is a constant which has the value 3.0 N/m3. Calculate Wforce, the work
done by this force, Wgrav, the work done by gravity, and the final speed of the block, vf, when the box is pushed
|3D
up to x = 4.0 m.
(A) Wforce = 192 J, Wgrav
39.2 J and vf = 15.2 m/s
(B) Wforce = 192 J, Wgrav = -39.2 J and vf = 12.4 m/s
%3D
%3D
(C) Wforce = 192 J, Wgrav = -39.2 J and vf = 15.2 m/s
%3D
4.0 m
(D) Wforce
48 J, Wgrav = 39.2 J and vf =
%3D
9.3 m/s
(E) Wforce = 48 J, Wgrav = -39.2 J and vf
9.3 m/s
(F) Wforce = 48 J, Wgrav =
%3D
39.2 J and vf = 12.4 m/s
F(x)
A block being INished up an incline by a
position-dependent force.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

DE REPORT 157% W ab] 4. A4.5 kg sed is pulled across level snow with a force of 225N on a rope that is 35 degrees above the horizontal. If the sled moves 65.3m In 2.5 minutes, how much work does the person do on the sled? How much power is exerted on the sled? The person is pulling as hard as possible on the rope. How else can the amount of work be increased?
1) Sarah pushes a heavy crate 3.0 meter along the floor at a constant speed. Known She pushes with a constant horizontal force of magnitude 70N. How much F = 70 N d = 3.0 m v = constant work does Sarah do on the crate? Find Before After W
W H mand 3 5. A boy pulls a 29.0-kg box with a 180-N force at 40° above a horizontal surface. If the coefficient of kinetic friction between the box and the horizontal surface is 0.23 and the box is pulled a distance of 30.0 m, what is the net work done on the box? E D 20 C Brow R F J T G 6 MacBook Air B 7 H - N 8 J M K MOSISO command شه
Work= force times distance: W=Fd Part A: Calculate the work done in ligting a 460-N barbell 1.8m above the floor? express your anser to two significant figures and include the appropriate units. PArt B: What is the gain of potential energy of the barbell when it is lifted to this height?
mike used his super muscle power to pull a box initially at rest, up an inclined plane. The inclined plane makes an angle of 35o with the horizontal and mike applied a force of 250 N parallel to the incline. The mass of the box is 25.0 kg and the coefficient of kinetic friction between the box and the surface is 0.45. The box moves up the incline at a distance of 5.0 m. Find the work done by the applied force. g = 9.81 m/s2
B3
Question 2 1. Two forces that are F, = 10N and F, = 5 N act on a body in a frictionless floor. If the displacement is 10 m, what is the work done by the forces on the body? Not yet answered Marked out of 2.00 F2 = 5 N F, = 10 N P Flag question Work done by the forces on the body = 2. A person of mass 70kg runs up a flight of stairs with a vertical height of 5m. If the trip takes 1 minute to complete, calculate the person's power. Power =
스크린샷 2022-03-30 오후 12.01.27 An external force F moves a 2.50-kg box at a constant speed v up a frictionless ramp, as shown in the figure. The force acts in a direction parallel to the ramp. 5.00 m -03. Calculate the work W done on the box by this force as it is pushed up the 5.00-m ramp to a height h = 3.00 m. 十 스크 -03. W = 스크로 -0. How does the work done on the box compare to the change in gravitational potential energy AU, that the grav box undergoes as it rises to its final height? O W > AUgrav W < AU grav O W = AU grav
(2) The combined force of lift and thrust on a model airplane is a constant F = (4î + 3j + 6k) N. a. How much work is done by the force F if the displacement of the airplane is: A = (6î – 5j – 3k) m? %3D b. Will this force cause the airplane to speed up, slow down or maintain a constant speed?
A child pulls a box of toys using a steady force of 10. N at an angle 60o from the horizontal. How much work is done by the child after the box moves with a distance of 4.0 m horizontally?
The spring in the above figure has a spring constant of K = 140 N/m. A 150 g block is placed against the spring which is then compress to 16 cm. A) When the block is released, how high up the slope does it rise? B) What is the kinetic energy at the highest point? C) What is the potential energy at the highest point?
Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 85.0 kg down a 60° slope at constant speed, as shown in the figure. The coefficient of friction between the sled and the snow is 0.100. (a) How much work is done by friction as the sled moves 30.0 m along the hill. Enter to 3 significant figures W fric (b) How much work is done by the rope on the sled in this distance? Hint: use Newton's second law to find the tension. Enter to 3 significant figures Wrope W. grav 60° J (c) What is the work done by the gravitational force on the sled? Enter to 3 significant figures J W₁ W J (d) What is the work done by the normal force? WN= J total (e) What is the total work done? Enter to 3 significant figures Note: When adding work done by individual forces, DO NOT ROUND THE VALUES TO FIND THE SUM. J Sense-making: If the speed of the rescue sled & the victim is constant, what do you expect the total work done on the rescue sled and the victim to be? Does your answer support…