A gas mixture at room temperature contains 10.0 mol CO and 12.5 mol 0,. (a) Compute the mole fraction of CO in the mixture. (b) The mixture is then heated, and the CÓ starts to react with the O, to give CO2: CO(g) + O2(g) –→ CO2(g) At a certain point in the heating, 3.0 mol CO, is present. Determine the mole fraction of CO in the new mixture.

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A gas mixture at room temperature contains 10.0 mol CO
and 12.5 mol 0,.
(a) Compute the mole fraction of CO in the mixture.
(b) The mixture is then heated, and the CÓ starts to react
with the O, to give CO2:
CO(g) + O2(g) –→ CO2(g)
At a certain point in the heating, 3.0 mol CO, is present.
Determine the mole fraction of CO in the new mixture.
Transcribed Image Text:A gas mixture at room temperature contains 10.0 mol CO and 12.5 mol 0,. (a) Compute the mole fraction of CO in the mixture. (b) The mixture is then heated, and the CÓ starts to react with the O, to give CO2: CO(g) + O2(g) –→ CO2(g) At a certain point in the heating, 3.0 mol CO, is present. Determine the mole fraction of CO in the new mixture.
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