Please answer correctly and in detail, I will upvote! Thank you. A galvanometer with a internal resistance of 40 N and a shunt resistor of valueRsh is connected in series with a 10 2 resistor. A constant voltage Vo is applied acrossthe circuit, and the galvanometer deflects a certain amount. The shunt resistor is thenremoved, and replaced in series with the 10N resistor. With the same voltage Vo, thegalvanometer deflection is unchanged. Calculate the value Rsh of the shunt resistor.

The value of the internal resistance is r=40 Ω The value of the series resistance with the shunt…

Answered: A galvanometer with a internal…

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