Half-ReactionE° (V)2H* (aq) + 2e¯ - H2 (9)0.000Ag* (aq) + e¯ → Ag (s)0.79962H20 (I) + 2e¯ - H2 (g) + 20OH" (aq)-0.8277AI3+ (aq) + 3e¯ → Al (s)-1.676H2O2 (aq) + 2H* (aq) + 2e¯ → 2H20 (1I)1.776Au+ (aq) + e¯→ Au (s)1.692I2 (s) + 2e¯ → 21¯ (aq)0.5355Au3+ (aq) + 3e¯ → Au (s)1.4982103- (aq) + 12H* (aq) + 10e¯ → I2 (s) + 6H2O (1)Mg2+ (aq) + 2e - Mg (s)1.195Ba2+ (aq) + 2e¯ → Ba (s)-2.912-2.372Br2 (1) + 2e¯ → 2B1¯ (aq)1.066Mn2+ (aq) + 2e" → Mn (s)-1.185Ca2+ (aq) + 2e¯ → Ca (s)-2.868Mno2 (s) + 4H+ (aq) + 2e¯ → Mn2+ (aq) + 2H20 (1)1.224Cl2 (g) + 2e¯ → 2C1- (aq)1.35827Mno4- (aq) + 8H* (aq) + 5e¯ → Mn2+ (aq) + 4H2O (1)1.507Co2+ (aq) + 2e¯ → Co (s)-0.28Mnog- (aq) + 2H20 (I) + 3e¯ → MnO2 (s) + 40H¯ (aq)0.595Co3+ (aq) + e¯ → Co2+ (aq)1.92HNO2 (aq) + H+ (aq) + e¯ → NO (g) + H2O (I)0.983Cr2+ (aq) + 2e¯ → Cr (s)-0.913N2 (g) + 4H2O (1) + 4e¯ → 40H" (aq) + N2H4 (aq)-1.16Cr3+ (aq) + 3e¯ → Cr (s)-0.744NO3- (aq) + 4H* (aq) + 3e¯ → NO (g) + 2H2O (1)0.957Cr3+ (aq) + e¯ → Cr2+ (aq)-0.407Na* (aq) + e¯ → Na (s)-2.71Cro42- (aq) + 4H20 (I) + 3e¯ → Cr(OH)3 (s) + 50H¯ (aq)-0.13Ni2+ (aq) + 2e" → Ni (s)-0.257Cu2+ (aq) + 2e¯ → Cu (s)0.341902 (g) + 4H* (aq) + 4e¯ → 2H20 (1)1.229Cu2+ (aq) + e- → Cu+ (aq)0.15302 (g) + 2H20 (1) + 4e¯ → 40H" (aq)0.401Cu* (aq) + e¯ → Cu (s)0.52102 (g) + 2H† (aq) + 2e¯ → H2O2 (aq)Pb2+ (aq) + 2e¯ → Pb (s)0.695F2 (g) + 2e¯ → 2F¯ (aq)2.866-0.1262Fe2+ (aq) + 2e¯ → Fe (s)-0.447PBSO4 (s) + H+ (aq) + 2e¯ → Pb (s) + HSO4¯ (aq)-0.3588Fe3+ (aq) + e- → Fe2+ (aq)Fe3+ (aq) + 3e¯ → Fe (s)0.771HSO4 (aq) + 3H+ (aq) + 2e¯ → H2SO3 (aq) + H2O (1)0.172-0.037Sc3+ (aq) + 3e - Sc (s)-2.077Sn2+(aq) + 2e¯ – Sn (s)-0.1375Sn4+ (aq) + 2e¯ →Sn2+ (aq)0.151VO2+ (aq) + 2H+ (aq) + e¯ →vo2+ (aq) + H20 (I)0.991Zn2+(aq) + 2e¯ →Zn (s)-0.7618 A galvanic cell is powered by the following redox reaction:2+3+O,(g) + 4H'(aq) + 4 Fe´'(aq)2 H20(1) + 4 Fe"(aq)Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab.Write a balanced equation forthe half-reaction that takesplace at the cathode.Write a balanced equation forthe half-reaction that takesplace at the anode.Calculate the cell voltageunder standard conditions.E° = [vRound your answer to 2decimal places.

E (cathode) = 1.229 V E (Anode) = -0.771 V

A galvanic cell is powered by the following redox reaction: O,(9) + 4 H"(ag) + 4 Fe2+ (aq) → 2 H,0(1) + 4 Fe*(aq) Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab. Write a balanced equation for the half-reaction that takes place at the cathode. Write a balanced equation for the half-reaction that takes place at the anode. Calculate the cell voltage under standard conditions. E = Iv Round your answer to 2 decimal places.

A galvanic cell is powered by the following redox reaction: O,(9) + 4 H"(ag) + 4 Fe2+ (aq) → 2 H,0(1) + 4 Fe*(aq) Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab. Write a balanced equation for the half-reaction that takes place at the cathode. Write a balanced equation for the half-reaction that takes place at the anode. Calculate the cell voltage under standard conditions. E = Iv Round your answer to 2 decimal places.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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