A galvanic cell is made of a Ni2+/Ni half cell with [Ni²+] = 1.00 × 10-3 M and a Ag*/Ag half cell with [Ag*] = 5.00 × 10-2 M. Calculate the electromotive force of the cell at 25 °C. F= 96500 C/mol, R=8.314 J/mol.K The reduction potentials for the two half cells are: Ni2*(aq) + 2e →Ni(s) E° = -0.24 V Ag*(aq) + e¯ –Ag(s) E° = +0.8 V O a. 1.09 O b. 1.04 O c. 1.06 O d. 0.98 O e. 1.12

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A galvanic cell is made of a Ni2+/Ni half cell with [Ni²+] = 1.00 × 10-3 M and a Ag*/Ag half
cell with [Ag*] = 5.00 x 10-2 M. Calculate the electromotive force of the cell at 25 °C.
F= 96500 C/mol, R=8.314 J/mol.K
The reduction potentials for the two half cells are:
Ni2+ (aq) + 2e →Ni(s) E° = -0.24 V
Ag*(aq) + e¯ →Ag(s) E° = +0.8 V
%3D
O a. 1.09
O b. 1.04
O c. 1.06
O d. 0.98
O e. 1.12
Transcribed Image Text:A galvanic cell is made of a Ni2+/Ni half cell with [Ni²+] = 1.00 × 10-3 M and a Ag*/Ag half cell with [Ag*] = 5.00 x 10-2 M. Calculate the electromotive force of the cell at 25 °C. F= 96500 C/mol, R=8.314 J/mol.K The reduction potentials for the two half cells are: Ni2+ (aq) + 2e →Ni(s) E° = -0.24 V Ag*(aq) + e¯ →Ag(s) E° = +0.8 V %3D O a. 1.09 O b. 1.04 O c. 1.06 O d. 0.98 O e. 1.12
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