A function f() is a one-way function if O y=f(x) is computationally easy and x=f-¹ (y) is computationally infeasible O y=f(x) is computationally infeasible and x=f-¹ (y) is computationally easy both y=f(x) andx=ƒ−¹ (y) is computationally infeasible both y=f(x) and x=f-¹ (y) is computationally easy

Q: The range of f(x)=/4-x² is [0,2] O (-00,2] [2,0) O [-2,0] [-2,2]

A: Range :- set of all output values

Q: E+ 4) for x e [O, of f(x)?

A:

Q: 2 (1)If f(x)=x² +x, g(x) = x+3 ' then fog(1)= go f(1) =.

A: Solve the given function

Q: 6. Use Euler's Formula to prove the following identities: eio terio cos O ei0 -e-i0 %3D and sin 0 =…

A: We have by Euler's formula, eiθ=cosθ+isinθ.....1e-iθ=cosθ-isinθ....2 Then adding equation (1) and…

Q: f(x)={0: x is less than or equal to -1, ax-b: -1 is less than x is less than 1, 3: x is greater than…

A: we have to find value of a and b so function to be continous

Q: D(x) is the price, in dollars per unit, that consumers are willing to pay for x units of an item,…

A: Given, Dx=e-x+3.5,Sx=ex-4.5

Q: Suppose f(x) is a differentiable function with f(-1) =2 and f(2) =-1. The differentiable function…

A:

Q: f(g(h(x)))=

A: Givenf(x)=x4+5, g(x)=x-4 and h(x)=x

Q: v(x) = {2(x − r) if (x − r ) ≥ 8 (3(x − r) if (x −r) < 0 a) Represent the value function…

A:

Q: Find f(x) and g(x) such that h(x) = (f o g)(x). Let g(x) = 3x + 1. 1 h(x) = V3x + 1 f(x) =D

A:

Q: What is the point of intersection for f(x) = 2* and g(x) = A (1,) (0,1) C (1,0) (2,4)

A:

Q: Let g(x) = VT + 3.

A: Given,  g(x)=x2+3

Q: 1. Determine f'(x) for each function below: f(x) = x2 – 2x + 3 f(x) = 7x3 · Vx %3D f(x) = x³ In x…

A: As per our company guidelines we are supposed to answer only first three sub-parts. Kindly repost…

Q: 1 x-2 f(x)=- y g(x)=√x

A: To find the composite function

Q: If f(x) = xª + 2, g(z) = x – 7 and h(x) = /¤, then f(g(h(x)))= Preview

A: We first plug h(x)=sqrt(x)

Q: Consider the function  f(x) = (x − 4)/( x + 2) .…

A: We have to say about the critical number 2 for the function: fx=x-4x+2 We know that we do calculate…