Answered: A frictionless spring with a 8-kg mass… | bartleby

Related questions

Question

A frictionless spring with a 8-kg mass can be
held stretched 1.2 meters beyond its natural length by
a force of 100 newtons. Find the position of the mass
after t seconds if the mass experiences a retarding
force equal to twice its velocity and it starts at a
velocity of 2 m/s:
meters

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A nucleus that captures a stray neutron must bring the neutron to a stop within the diameter of the nucleus by means of the strong force. That force, which "glues" the nucleus together, is approximately zero outside the nucleus. Suppose that a stray neutron with an initial speed of 1.1 × 10' m/s is just barely captured by a nucleus with diameter d = 1.5 × 1014 m. Assuming that the strong force on the neutron is constant, find the magnitude of that force. The neutron's mass is 1.67 x 1027 kg. %3D Number Units
6- A 900 g particle has velocity vx = -5.0 m/s at t = -2 s. Force Fx (t) = 50.et Newton is exerted on the particle between t = -2 s and t = +2 s. This force increases from 0.0N at t = - 2 s to 20.0N at t = 0s and then back to 0 N at t = 2 s. What is the particle's velocity at t = 2 s?
A hockey puck with mass 0.166 kg is pushed across the ice with a constant force of 0.89 N. The coefficient of kinetic friction between the puck and the ice is 0.22. After a distance of 2.6 m, what is the puck's speed in m/s?
2. A 1.0 kg block initially at rest falls vertically and lands on a massless spring. Assume that the block comes to a stop momentarily after it compresses the spring. The block is initially 0.1 m away from the spring and the spring constant k = 1000 N/m. Use g = 9.8 m/s2 as the gravitational acceleration. (a) (b) subsequent state of motion of the block and explain your answer. %3D How much is the spring compressed? What happens after the block comes to a momentary stop? That is, analyze the
If a 2.1 kg object is initially at rest on a frictionless, horizontal surface and subjected to a 13.7 N force in the positive x-direction over a distance of 3.49 meters, what will the object's final speed be? Assume the answer in in m/s.
Problem 18: A particle of mass 0.61 kg begins at rest and is then subject to a force in the positive x direction that changes with time as given by the following function: F = mg[1-e-3.1t ], where g is the acceleration due to gravity. Δv = 19.38 Determine the change in x-coordinate of the particle Δx between t = 0 and t = 2.3.
Problem 2: An object of mass M is hanging from a spring (with I_o =0 and a spring constant k). There is a constant force from the wind, F_wind, blowing to the right, so the mass is initially at rest, but hanging at an angle Theta from the vertical because of the presence of the wind. Suddenly, spring breaks, and the mass drops under the influence of F_wind (note F_air and F_wind are the same constant vector!) and its weight. If the object (in equilibrium before the spring breaks) is a height H above the ground, how far laterally (in the direction of the wind) does the object hit the ground, L (given theta, k, M, g, H)?
If a 2.3 kg object is initially at rest on a frictionless, horizontal surface and subjected to a 10.2 N force in the positive x-direction over a distance of 4.1 meters, what will the object’s final speed be? Assume the answer in in m/s.
The 20-kg block is subjected to the forces shown. Motion occurs to the right. In case (b) shown in (Figure 2) determine the speed of the block at s=6 m if v= 3 m/s at s= 0.
A horizontal force of 80.0 N is applied to a 5.00 kg block as the block slides a distance of 0.800 m along a horizontal floor. The coefficient of kinetic friction between the floor and the block is 0.500. If the block is initially at rest, how fast is it moving at the end of the displacement?
Substituting, for the coefficient of kinetic friction, we find Xn = 0.25 3 6 m m +); 2 10 (2 451 N/m) ( 0.36 9 ) (25/ 06-6) (CM (ત્ર m m X ney Pi1991 fan of ap by ne anen f S OX
Your answer is partially correct. The only force acting on a 4.5 kg body as it moves along the positive x axis has an x component F,= -4x N, where x is in meters. The velocity of the body at x = 1.4 m is 10 m/s. (a) What is the velocity of the body at x = 3.2 m? (b) At what positive value of x will the body have a velocity of 2.0 m/s? (a) Number 9.62 (b) Number 1.94 eTextbook and Media Units Units m/s m