A frame ABC is supported in part by cable DBE that passes through a frictionless ring at B. Knowing that the tension in the cable is 385 N, determine (a)- the resultant (R) of the forces as a vector which exerted by the cables on the support at D and E, (b)- the angles between R and each of the coordinate axes. Answer: 250 mm 210 mem R= Fgp + FRg =-(375 N)i +(455 N)j-(460 N)k BD 8, =120.1° 0, = 52.5° %3D 510 mm 400 mm 0. =128.0° 600 mm 180 mm

A frame ABC is supported in part by cable DBE that passes through a frictionless ring at B. Knowing that the tension in the cable is 385 N, determine (a)- the resultant (R) of the forces as a vector which exerted by the cables on the support at D and E, (b)- the angles between R and each of the coordinate axes. Answer: 250 mm 210 mem R= Fgp + FRg =-(375 N)i +(455 N)j-(460 N)k BD 8, =120.1° 0, = 52.5° %3D 510 mm 400 mm 0. =128.0° 600 mm 180 mm

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

H.W:
A frame ABC is supported in part by cable DBE that passes through a frictionless ring at B. Knowing that the
tension in the cable is 385 N, determine (a)- the resultant ( R ) of the forces as a vector which exerted by the
cables on the support at D and E, (b)- the angles between R and each of the coordinate axes.
Answer:
250 mm
210 mm
R= Fap +FRg =-(375 N)i + (455 N)j-(460 N)k
%3D
BE
0, =120.1°
8, = 52.5°
510 mm
400 mm
0. =128.0°
600 mm
480 mm

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