A four pole 60 Hz wound rotor motor is to be used as a frequency converter. At what speed must the rotor be driven, and in what direction must it rotate, if the output frequency is to be: a. 90 cycles (900) b. 150 cycles ( 2,700) c. 50 cycles (300) what will be the rotor frequency if the speed is d. 2,200 rpm against the field's direction ( 133 1/3cps) e. 400 rpm in the same direction ( 46 2/3 cps ) Solution The four-pole 60-cycle synchronous speed of the revolving field is 1,800 rpm. (a) 90 - 60 + rpm.on 1,800 (90 rpmons = 60 (器-) 1,800 900 opposite direction 150 (b) rpm.on = 1,800 2,700 opposite direction %3D 60 rpm.ons 1,800 (c) 50 - 60 (1 - ) 1,800 - 300 same direction rpmn - 2,200 1,800 133 cps (d) fo. - 60 400 - 60 1,800 463 eps

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In this problem, how could I know what will be the direction must the motor would rotate?

2 1 .• 3
4
A four pole 60 Hz wound rotor motor is to be used as a frequency converter. At
what speed must the rotor be driven, and in what direction must it rotate,
if the output frequency is to be:
a. 90 cycles ( 900 )
b. 150 cycles ( 2,700)
c. 50 cycles (300)
what will be the rotor frequency if the speed is
d. 2,200 rpm against the field's direction ( 133 1/3cps)
e. 400 rpm in the same direction ( 46 2/3 cps )
Solution
The four-pole 60-cycle synchronous speed of the revolving field is 1,800
rpm.
rpm.onv
1,800
(a)
90 60 (1+
06,
| 1,800
900 opposite direction
rpm.con =
%3D
60
150
1) 1,800 = 2,700 opposite direction
%3D
(b)
rpm.con =
60
rpm.conv
1,800
(c)
50
60 ( 1
%3D
50
1,800 = 300 same direction
60
rpmono
2,200
60 (1+
1,800
133 cps
%3D
(d)
fom
400
46% cps
%3D
(e)
= 60 ( 1
1,800
dalivered hv a frequanev converter varies dirently
Transcribed Image Text:2 1 .• 3 4 A four pole 60 Hz wound rotor motor is to be used as a frequency converter. At what speed must the rotor be driven, and in what direction must it rotate, if the output frequency is to be: a. 90 cycles ( 900 ) b. 150 cycles ( 2,700) c. 50 cycles (300) what will be the rotor frequency if the speed is d. 2,200 rpm against the field's direction ( 133 1/3cps) e. 400 rpm in the same direction ( 46 2/3 cps ) Solution The four-pole 60-cycle synchronous speed of the revolving field is 1,800 rpm. rpm.onv 1,800 (a) 90 60 (1+ 06, | 1,800 900 opposite direction rpm.con = %3D 60 150 1) 1,800 = 2,700 opposite direction %3D (b) rpm.con = 60 rpm.conv 1,800 (c) 50 60 ( 1 %3D 50 1,800 = 300 same direction 60 rpmono 2,200 60 (1+ 1,800 133 cps %3D (d) fom 400 46% cps %3D (e) = 60 ( 1 1,800 dalivered hv a frequanev converter varies dirently
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