A four bar mechanism(attached) is required to satisfy the following two positions. Q2 Q4 Position 1 0° 102° Position 2 90° 109.4° At position 2 ,speed of output crank will be 2 rad/sec CCW , while the speed of the input crank is 4 rad/sec CCW. Make a1=10 cm.
A four bar
| Q2 | Q4 | |
| Position 1 | 0° | 102° |
| Position 2 | 90° | 109.4° |
At position 2 ,speed of output crank will be 2 rad/sec CCW , while the speed of the input crank is 4 rad/sec CCW. Make a1=10 cm.
Q̇4=+2 rad/sec.
Q̇2=+4 rad/sec.
K1*cos(102)-K2*cos(0)+K3=cos(102-0) -------------------1st equation
K1*cos(109.4)-K2*cos(90)+K3=cos(109.4-90) ------------2nd equation
-K1*2*sin(109.4)+K2*4*sin(90)=-(4-2)*sin(109.4-90)----3rd equation
Once link dimensions are found , draw the mechanism two times , with input crank angles 0° and 90° and measure the output angles Q4 , to see whether they are 102° and 109.4°. then do a velocity analysis for position 2, and find the angular velocity of link 4 , when link 2 is rotating CCW with a speed of 4 rad/sec, to see if it is 2 rad/sec CCW or not.
Step by step
Solved in 3 steps with 3 images
