A force of 75 N is applied to a 13 Kg box sliding across a table where the coefficient of friction is 0.28. Use the diagram below to match each item to the correct value. No units are used in this question. Fnorm = Ffrict = P= m = a = Fnet = Fgrav = Fapp = ✓ What is the net force acting on the box? A. 100 What is the acceleration of the box? B. 3.0 ✓ What is the normal force? C. 4.9 ✓ What is the force of gravity (weight) on the box? D. 38.6 E. 130
A force of 75 N is applied to a 13 Kg box sliding across a table where the coefficient of friction is 0.28. Use the diagram below to match each item to the correct value. No units are used in this question. Fnorm = Ffrict = P= m = a = Fnet = Fgrav = Fapp = ✓ What is the net force acting on the box? A. 100 What is the acceleration of the box? B. 3.0 ✓ What is the normal force? C. 4.9 ✓ What is the force of gravity (weight) on the box? D. 38.6 E. 130
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![A force of 75 N is applied to a 13 Kg box sliding across a table where the coefficient of friction is 0.28. Use the diagram below to
match each item to the correct value. No units are used in this question.
Fnorm =
Ffrict =
P=
m =
a =
Fnet =
Fgrav =
Fapp =
✓ What is the net force acting on the box?
A. 100
What is the acceleration of the box?
B. 3.0
✓ What is the normal force?
C. 4.9
✓ What is the force of gravity (weight) on the box? D. 38.6
E. 130](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc04d048-dffc-49e7-a4c6-b7e32c98d52a%2F1aef85d9-648c-49d2-ae76-5dd9e4b6b78e%2F4aboic_processed.png&w=3840&q=75)
Transcribed Image Text:A force of 75 N is applied to a 13 Kg box sliding across a table where the coefficient of friction is 0.28. Use the diagram below to
match each item to the correct value. No units are used in this question.
Fnorm =
Ffrict =
P=
m =
a =
Fnet =
Fgrav =
Fapp =
✓ What is the net force acting on the box?
A. 100
What is the acceleration of the box?
B. 3.0
✓ What is the normal force?
C. 4.9
✓ What is the force of gravity (weight) on the box? D. 38.6
E. 130
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