A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 6 m/s. Give the initial conditions. x(0) = x'(0) = m m/s Find the equation of motion. x(t) = m
A force of 720 newtons stretches a spring 4 meters. A mass of 45 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 6 m/s. Give the initial conditions. x(0) = x'(0) = m m/s Find the equation of motion. x(t) = m
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter16: Oscillations
Section: Chapter Questions
Problem 11PQ: A 1.50-kg mass is attached to a spring with spring constant 33.0 N/m on a frictionless, horizontal...
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