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a) For two inductors in series as in Figure 6.81a), show that the voltage division principle is L, L2 Us L¡ + L2 U2 L, + L2 b) For two inductors in parallel as in Figure 6.81b), show that the principle of current division is L1 -i, L¡ + L2 L2 iz = i L, + L2 ell i2 + U2 L2 L2 a) b) ll lll ll

a) For two inductors in series as in Figure 6.81a), show that the voltage division principle is L, L2 Us L¡ + L2 U2 L, + L2 b) For two inductors in parallel as in Figure 6.81b), show that the principle of current division is L1 -i, L¡ + L2 L2 iz = i L, + L2 ell i2 + U2 L2 L2 a) b) ll lll ll

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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a) For two inductors in series as in Figure 6.81a), show that the voltage division principle is L, L2 Us L¡ + L2 U2 L, + L2 b) For two inductors in parallel as in Figure 6.81b), show that the principle of current division is L1 -i, L¡ + L2 L2 iz = i L, + L2 ell i2 + U2 L2 L2 а) b) ll lll ll
Transcribed Image Text:a) For two inductors in series as in Figure 6.81a), show that the voltage division principle is L, L2 Us L¡ + L2 U2 L, + L2 b) For two inductors in parallel as in Figure 6.81b), show that the principle of current division is L1 -i, L¡ + L2 L2 iz = i L, + L2 ell i2 + U2 L2 L2 а) b) ll lll ll
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