(a) For the BJT VBB = 2.5V; RB = 4.7 kS; Ic (sat) = 18 mA, VCE (sat) = 0.5 mV and BDc = 80. i) Calculate the value of IB and Rc. ii) configuration in the Figure 1, the following values is given: Vcc=25V; 111) Determine whether the transistor of BJT configuration is saturated or not and justify your answer. What will be happened to the transistor if the IB is changed to 0.25 times from origin values?

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BJT (Bipolar Junction Transistor)

A BJT is a semiconductor device with 3 terminals that consist of a p-n junction diode that can amplify the signal or current. It is a current-controlled device. The three BJT terminals are base, collector, and emitter. The BJT works with the charge carrier, the two type of carriers in the BJT are holes and electrons, the charge carriers flow by the process of recombination. The signal to be amplifier is generally given as the input at the base terminal and an amplified form of it is available at the collector terminal.