Patient123400 PEEAE101112131415161719982021222324252627282930Weight in Lbs1st 2nd 3rd155145140187178165185180183190185180210200195201196200199186188190185186188180175175160153167155150178170172166 160 163185177168201190189210197 200205 195201193 191190182185174259 236 240239226 221164 157156197196193222201200211196 195187181180175164170186 181180243229220246231 225Anova: Single FactorSUMMARY1st2nd3rdANOVASource of VariationBetween GroupsWithin GroupsTotalGroupsCount3030302209.44860750816Sum Average Variance5896 196.53 636.19514.135602 186.735563 185.43 525.77MSF F-valua Font1104.7 1.9773 0.1446 3.1013558.728789F crit1.95 DA food nutritionist provides a program to help their clients lose weight and asks toinvestigate the effectiveness of the program. The nutritionist takes a sample of 30 people,weighing each person in the sample before the program begins and 2 months later.Determine whether the program is effective at 95% confidence level.Download the file: food nutritionistKindly click True after Copying the problem and Downloading the file.

First we State hypothesis for the above situation. Null hypothesis, H0: There is no difference in…

Answered: A food nutritionist provides a program…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You may need to use the appropriate technology to answer this question. Periodically, customers of a financial services company are asked to evaluate the company's financlal consultants and services. Higher ratings on the client satisfaction survey indicate better service, with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use a = 0.05 and test to see whether the consultant with more experience has the higher population mean service rating. ConsultantA Consultant B = 16 n2 = 10 x, 6.83 x2 = 6.28 5- 0.68 52 = 0.75 (a) State the null and alternative hypotheses. O Ho: H1- H2 * 0 H: H-H2=0 O Ho: H-H2> o Ho Hy-H250 H -H2>0 O Ho: H-H2=o H: H-H2 0 O Ho: H-H25o H H-H2 0 (b) Compute the value of the test statistic. (Round your answer to three decimal places.) (c) What is the p-value? (Round your answer to four decimal places.) p-value…
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Researchers examined the influence of a television program on children's aggressiveness. The number of aggressive responses was measured during an observation period after viewing the television program. Imagine that the known national average for number of aggressive responses typically performed by children who do not watch television is 6.847. Use the data below to conduct an analysis to determine if the number of aggressive responses on average is different from the national average. The data for this study can be found below, answer questions based on data. What is the null and alternative hypotheses in words and symbols? Is the assumption(s) met? Please explain your answer and proceed with the analysis even if the assumption(s) is not met. What do you conclude from your analysis? Based on your response in “c” above, identify and explain the type of error you could be making. responses 9 4 11 12 14 7 12 10 11 8 14 12 8 12 7 10 10 9 5…
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