A flywheel with a radius of 0.400 m starts from rest and accelerates with a constant angular acceleration of 0.700 rad/s?. Part B Compute the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its rim after it has turned through 60.0°. Express your answers in meters per second squared separated by commas. atan =, arad =, atotal = m/s, m/s?, m/s Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining Part C Compute the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its rim after it has turned through 120°. Express your answers in meters per second squared separated by commas. atan =, arad =, atotal = m/s, m/s, m/s Submit Previous Answers Request Answer
A flywheel with a radius of 0.400 m starts from rest and accelerates with a constant angular acceleration of 0.700 rad/s?. Part B Compute the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its rim after it has turned through 60.0°. Express your answers in meters per second squared separated by commas. atan =, arad =, atotal = m/s, m/s?, m/s Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining Part C Compute the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its rim after it has turned through 120°. Express your answers in meters per second squared separated by commas. atan =, arad =, atotal = m/s, m/s, m/s Submit Previous Answers Request Answer
A flywheel with a radius of 0.400 m starts from rest and accelerates with a constant angular acceleration of 0.700 rad/s?. Part B Compute the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its rim after it has turned through 60.0°. Express your answers in meters per second squared separated by commas. atan =, arad =, atotal = m/s, m/s?, m/s Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining Part C Compute the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its rim after it has turned through 120°. Express your answers in meters per second squared separated by commas. atan =, arad =, atotal = m/s, m/s, m/s Submit Previous Answers Request Answer
A flywheel with a radius of 0.400 mm starts from rest and accelerates with a constant angular acceleration of 0.700 rad/s2rad/s2.
Transcribed Image Text:I Review | Constants
Correct
A flywheel with a radius of 0.400 m starts from rest
and accelerates with a constant angular acceleration
of 0.700 rad/s?.
Part B
Compute the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its
rim after it has turned through 60.0°.
Express your answers in meters per second squared separated by commas.
m/s², m/s°, m/s
atan =, Arad =, atotal =
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 2 attempts remaining
Part C
Compute the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its
rim after it has turned through 120°.
Express your answers in meters per second squared separated by commas.
atan =, arad =, atotal =
m/s?, m/s, m/s?
Submit
Previous Answers Request Answer
Definition Definition Rate of change of angular velocity. Angular acceleration indicates how fast the angular velocity changes over time. It is a vector quantity and has both magnitude and direction. Magnitude is represented by the length of the vector and direction is represented by the right-hand thumb rule. An angular acceleration vector will be always perpendicular to the plane of rotation. Angular acceleration is generally denoted by the Greek letter α and its SI unit is rad/s 2 .
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
