An object starts from a rest and undergoes a circular motion for a period of 4.41s until it turns at the rate of 246/s. Calculate the angular acceleration of the object in rad/s.
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A: See below
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The equation of rotational motion is given by,
Here,ωo, ω denotes the initial and final angular velocity respectively, α denotes the angular acceleration and t denotes the time.
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- What constant angular acceleration is required to reduce an object's angular velocity from 36.1 rad/s to 14.9 rad/s over 14 revolutionsStarting from rest, a wheel reaches and angular speed of 5.435 π rad/s in 12.65 s.a) Find the magnitude of the angular acceleration of the wheel.b) Through what angle does the wheel move in 6.325 s?A dentist's drill starts from rest. After 3.00 s of constant angular acceleration it turns at a rate of 2.80 ✕ 104 rev/min. (a) Find the drill's angular acceleration. rad/s2(b) Determine the angle (in radians) through which the drill rotates during this period. rad
- A machine part has the shape of a solid uniform sphere of mass 235 g and diameter 4.50 cm. It is spinning about a frictionless axle through its center, but at one point on its equator it is scraping against metal, resulting in a friction force of 0.0200 N at that point.A playground merry-go-round has a radius of 3.5 m and a rotational inertia of 720 kgˑm2. It is initially spinning at 0.60 rad/s when a 25 kg child crawls from the center to the rim. When the child reaches the rim the angular velocity of the merry-go-round in rad/s is:A turn table starts from rest and reaches 11 rad/s of angular velocity in 9.5 s. Find the angular acceleration in rad/s/s. Answer:
- A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 12.0 rad/s in 3.00 s. Find (a) the magnitude of the angular acceleration of the wheel and Answer 4.00 rad/s^2 (b) the angle in radi-ans through which it rotates in this time interval. Answer 18.0 radA dentist's drill starts from rest. After 3.10 s of constant angular acceleration it turns at a rate of 2.70 ✕ 104 rev/min. (a) Find the drill's angular acceleration. (b) Determine the angle (in radians) through which the drill rotates during this period.How much time elapses while it turns through 300 radians? O 11.0 s O 12.7 s O 15.8 s O none of the above
- A figure skater performs a twisting jump. She rotates around her longitudinal axis 2 times in 0.65 s. What was her average angular velocity in radians/second? A 720rad/s B 19.3rad/s C 4? rad/s D 9.67 rad/s E 1107 rad/sA power drill starts from rest and undergoes uniform angular acceleration for a period of 0.175 s until it turns at a rate of 3.00 ✕ 104 rev/min. (a)What is the drill's angular acceleration (in rad/s2)? (Enter the magnitude.) rad/s2 (b)What is the angle (in radians) through which the drill rotates during this period? (Enter the magnitude.) radthe angular velcoity of an airplane propeller increases from 12 rad/s to 16 rad/s while turning through 7 rad. What is the angular acceleration in rad/s^2?