Can you help me solve this question? A fluid flow through two horizontal circular pipes that are connected together in series. Thelength of pipe 1 is twice that of pipe 2 (LI = 2L2), and the flow is laminar in each pipe. Thepressure drop in pipe 1 equals twice the pressure drop in pipe 2. If the diameter of pipe 1 is 1.0m, find the diameter of pipe 2 in mm. Ignore frictional losses due to the abrupt change in theflow path where the two pipes are connected. Show your analysis.

Answered: A fluid flow through two horizontal…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A fluid flow through two horizontal circular pipes that are connected together in series. The
length of pipe 1 is twice that of pipe 2 (LI = 2L2), and the flow is laminar in each pipe. The
pressure drop in pipe 1 equals twice the pressure drop in pipe 2. If the diameter of pipe 1 is 1.0
m, find the diameter of pipe 2 in mm. Ignore frictional losses due to the abrupt change in the
flow path where the two pipes are connected. Show your analysis.

Expert Solution

Step 1

$G i v e n d a t a \to h o r i z o n t a l c i r c u l a r p i p e s c o n n e c t e d i n s e r i e s L_{1} = 2 L_{2} f l o w i s l a m i n a r p r e s s u r e d r o p i n p i p e 1 i s e q u a l t o t w i c e t h e p r e s s u r e d r o p i n p i p e 2 \frac{P_{1}}{ρ g} = 2 \times \frac{P_{2}}{ρ g}$

ignore frictional losses due to abrupt change

applying bernoulli equation at in pipes connected in series.

since both the pipes are hoprizontal so $Z_{1} = Z_{2}$

$\frac{P_{1}}{ρ g} + \frac{v_{1}^{2}}{2 g} = \frac{P_{2}}{ρ g} + \frac{v_{2}^{2}}{2 g}$

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