A floor slab 100 mm thick is cast monolithically with beams 250 mm wide 450 mm deep spaced 1.2 m on centers, on simple supports overa span of 5.0 m. The floor supports a superimposed service dead load of 1.0 kPa and service live load of 2.1 kPa. Using f. = 21 MPa, long bar f, = 415 MPa, calculate the following: Factored uniform load on a typical interior beam in kN/m using load factors of 1.2 1. for dead load and 1.6 for live load. А. 8.928 В. 11.448 С. 11.028 D. 9.960 2. Effective flange width of a typical interior beam in mm. A. 1,500 В. 1,850 С. 1,200 D. 1,466 3. Required amount of 16-mm-flexure bars for a typical interior beam in positive bending. Use 10-mm-dia. stirrups A. 512 mm? В. 246 mm? C. 331 mm? D. 427 mm?

A floor slab 100 mm thick is cast monolithically with beams 250 mm wide 450 mm deep spaced 1.2 m on centers, on simple supports overa span of 5.0 m. The floor supports a superimposed service dead load of 1.0 kPa and service live load of 2.1 kPa. Using f. = 21 MPa, long bar f, = 415 MPa, calculate the following: Factored uniform load on a typical interior beam in kN/m using load factors of 1.2 1. for dead load and 1.6 for live load. А. 8.928 В. 11.448 С. 11.028 D. 9.960 2. Effective flange width of a typical interior beam in mm. A. 1,500 В. 1,850 С. 1,200 D. 1,466 3. Required amount of 16-mm-flexure bars for a typical interior beam in positive bending. Use 10-mm-dia. stirrups A. 512 mm? В. 246 mm? C. 331 mm? D. 427 mm?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A simply supported wood beam AB with span length L = 3.5 m carries a uniform load of intensity q = 6.4 kN/m (see figure). 9 B tod Calculate the maximum flexural stress due to the load q if the beam has a rectangular L
A floor slab 100 mm thick is cast monolithically with beams 250 mm wide 450 mm deep spaced 1.2 m on centers, on simple supports over a span of 5.0 m. The floor supports a superimposed service dead load of 1.0 kPa and service live load of 2.1 kPa. Using Pc= 21 MPa, long bar fy = 415 MPa, calculate the following: 1. Factored uniform load on a typical interior beam in kN/m using load factors of 1.2 for dead load and 1.6 for live load. A. 8.928 B. 11.448 C. 11.028 2. Effective flange width of a typical interior beam in mm. D. 4.960 A. 1,500 B. 1,850 C. 1,200 3. D. 1,466 Required amount of 16-mm-flexure bars for a typical interior beam in positive bending. Use 10-mm-dia. stirrups A. 512 mm2 B. 246 mm? C. 331 mm? D. 427 mm2
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A floor slab 100 mm thick is cast monolithically with beams 250 mm wide 450 mm deep spaced 1.2 m on centers, on simple supports over a span of 5.0 m. The floor supports a superimposed service dead load of 1.0 kPa and service live load of 2.1 kPa. Usingf.-21 MPa, long bar f, = 415 MPa, calculate the following: 1. Factored uniform load on a typical interior beam in kN/m using load factors of 12 for dead load and 1.6 for live load. B. 11.448 Effective flange width of a typical interior beam in mm. B. 1,850 A 8.928 C 11.028 D. 9.960 2. A 1,500 Required amount of 16-mm-flexure bars for a typical interior beam in positive bending Use 10-mm-dia. stirrups C. 1,200 D. 1,466 3. B. 246 mm C.331 mm D. 427 mm A 512 mm ?
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