A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is i = (12.0 î − 2.60 ĵ) m. After the fish swims with constant acceleration for 15.0 s, its velocity is  = (25.0 î − 1.00 ĵ) m/s. (a) What are the components of the acceleration of the fish? ax =   ay =   (b) What is the direction of its acceleration with respect to unit vector î?   Draw coordinate axes on a separate piece of paper, and then add the acceleration vector with its tail at the origin. Write the numerical values for the x and y components and then use this drawing to determine the angle.° counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t = 28.0 s? x =  m y =  m In what direction is it moving?  ° counterclockwise from the +x-axis

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Projectile Motion