(a) Find wo1 and Q1 for the first second-order section with transfer function 1.4587 × 107 H,(s) : s2 %3D + 4868.2138s + 1.4587 × 107 (b) Find the normalized component values for the first second-order section with transfer function H1(s).
(a) Find wo1 and Q1 for the first second-order section with transfer function 1.4587 × 107 H,(s) : s2 %3D + 4868.2138s + 1.4587 × 107 (b) Find the normalized component values for the first second-order section with transfer function H1(s).
Introductory Circuit Analysis (13th Edition)
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![### Design and Analysis of a Fourth Order Lowpass Filter
#### Transfer Function
The transfer function of the fourth-order lowpass filter is given by:
\[
H(s) = \frac{1.4587 \times 10^7}{s^2 + 4868.2138s + 1.4587 \times 10^7} \times \frac{5.1506 \times 10^7}{s^2 + 2016.4802s + 5.1506 \times 10^7}
\]
#### Filter Design
To design this filter, we will cascade two Sallen-Key second-order lowpass filters using the equal R, equal C method. The Sallen-Key second-order lowpass filter schematic is shown below. The resistors \( R_a \) and \( R_b \) are chosen to provide a gain of 1 when \( \omega = 0 \). The design constant \( k_m \) is set at 1000.

#### Problem Statements
(a) **Find \(\omega_{01}\) and \(Q_1\)** for the first second-order section with transfer function:
\[
H_1(s) = \frac{1.4587 \times 10^7}{s^2 + 4868.2138s + 1.4587 \times 10^7}
\]
(b) **Determine the Normalized Component Values** for the first second-order section based on the transfer function \( H_1(s) \).
#### Schematic Details
- **Input**: \( V_{in} \)
- **Output**: \( V_o \)
- **Components**:
- **Capacitors**: \( C1 \), \( C2 \)
- **Resistors**: \( R_a \), \( R_b \), \( R2 \)
- **Operational Amplifier**: \( U1 \) (configured in a Sallen-Key topology)
This setup is crucial for achieving the desired frequency response, allowing flexibility in tuning \(\omega_0\) and \(Q\).
### Steps and Calculations
The text does not cover specific calculations but prompts the reader to solve for the natural frequency \(\omega_{01}\) and quality factor \(Q_1\), then normalize component values for practical implementation in circuit design.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd230794e-e523-4ec2-92f4-d9c51a06a3bf%2Ff791f7be-7b32-442c-b557-6a0caa46162c%2F2omht9_processed.png&w=3840&q=75)
Transcribed Image Text:### Design and Analysis of a Fourth Order Lowpass Filter
#### Transfer Function
The transfer function of the fourth-order lowpass filter is given by:
\[
H(s) = \frac{1.4587 \times 10^7}{s^2 + 4868.2138s + 1.4587 \times 10^7} \times \frac{5.1506 \times 10^7}{s^2 + 2016.4802s + 5.1506 \times 10^7}
\]
#### Filter Design
To design this filter, we will cascade two Sallen-Key second-order lowpass filters using the equal R, equal C method. The Sallen-Key second-order lowpass filter schematic is shown below. The resistors \( R_a \) and \( R_b \) are chosen to provide a gain of 1 when \( \omega = 0 \). The design constant \( k_m \) is set at 1000.

#### Problem Statements
(a) **Find \(\omega_{01}\) and \(Q_1\)** for the first second-order section with transfer function:
\[
H_1(s) = \frac{1.4587 \times 10^7}{s^2 + 4868.2138s + 1.4587 \times 10^7}
\]
(b) **Determine the Normalized Component Values** for the first second-order section based on the transfer function \( H_1(s) \).
#### Schematic Details
- **Input**: \( V_{in} \)
- **Output**: \( V_o \)
- **Components**:
- **Capacitors**: \( C1 \), \( C2 \)
- **Resistors**: \( R_a \), \( R_b \), \( R2 \)
- **Operational Amplifier**: \( U1 \) (configured in a Sallen-Key topology)
This setup is crucial for achieving the desired frequency response, allowing flexibility in tuning \(\omega_0\) and \(Q\).
### Steps and Calculations
The text does not cover specific calculations but prompts the reader to solve for the natural frequency \(\omega_{01}\) and quality factor \(Q_1\), then normalize component values for practical implementation in circuit design.
![(c) Find the scaled (both magnitude and frequency) component values for the first second-order section with transfer function \( H_1(s) \).
(d) Find \(\omega_{02}\) and \(Q_2\) for the second second-order section with transfer function
\[
H_2(s) = \frac{5.1506 \times 10^7}{s^2 + 2016.4802s + 5.1506 \times 10^7}
\]
(e) Find the normalized component values for the second second-order section with transfer function \( H_2(s) \).
(f) Find the scaled (both magnitude and frequency) component values for the second second-order section with transfer function \( H_2(s) \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd230794e-e523-4ec2-92f4-d9c51a06a3bf%2Ff791f7be-7b32-442c-b557-6a0caa46162c%2Feg8hv4_processed.png&w=3840&q=75)
Transcribed Image Text:(c) Find the scaled (both magnitude and frequency) component values for the first second-order section with transfer function \( H_1(s) \).
(d) Find \(\omega_{02}\) and \(Q_2\) for the second second-order section with transfer function
\[
H_2(s) = \frac{5.1506 \times 10^7}{s^2 + 2016.4802s + 5.1506 \times 10^7}
\]
(e) Find the normalized component values for the second second-order section with transfer function \( H_2(s) \).
(f) Find the scaled (both magnitude and frequency) component values for the second second-order section with transfer function \( H_2(s) \).
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