(a) Find the real and positive constants n and y such that the following velocity field V is conservative V(x, y, z)= [2ŋx sin(z)] i+ [√y z²e¯ ]] + [x² cos(z) - 2ze->] k (b) Consider a force field F(x, y, z)=(x, y, z) where is the conservative form of V from part (a). Find o such that F= Vo. (c) Can the divergence of F be zero on the plane z=0? Justify your answer using the divergence of F on this plane. Classify the points on z=0 as source, sink or neither.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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(a) Find the real and positive constants n and y such that the following velocity field V is
conservative
V(x, y, z) = [2ŋx sin(z)] i+[√y z²e¯ ]] + [x² cos(z) - 2ze->] k
(b) Consider a force field F(x, y, z)=(x, y, z) where is the conservative form of V
from part (a). Find o such that F = Vo.
(c) Can the divergence of F be zero on the plane z=0? Justify your answer using the
divergence of F on this plane. Classify the points on z=0 as source, sink or neither.
Transcribed Image Text:(a) Find the real and positive constants n and y such that the following velocity field V is conservative V(x, y, z) = [2ŋx sin(z)] i+[√y z²e¯ ]] + [x² cos(z) - 2ze->] k (b) Consider a force field F(x, y, z)=(x, y, z) where is the conservative form of V from part (a). Find o such that F = Vo. (c) Can the divergence of F be zero on the plane z=0? Justify your answer using the divergence of F on this plane. Classify the points on z=0 as source, sink or neither.
1. Change of Variable of Integration in 2D
[ f(x,y) drdy = f(z(u, v),y(u, 0)). («, ») ducho
2. Transformation to Polar Coordinates
The useful formulas
3. Change of Variable of Integration in 3D
[, (2, 2) dadydz = [[F(w, x, w)|J(u, v, w)| dududw
4. Transformation to Cylindrical Coordinates
z=rcos, y=rsin, Jr.)=r
6. Line Integrals
5. Transformation to Spherical Coordinates
x=rcos 0, y = rsin, ===, J(r,0,2)=r
x=rcos@sind, y=rsin@sind, 2=rcoso, Jr.,0,0)=²sin
7. Work Integrals
[1(x, y, z) ds = [ f(x(t), y(t),= (t)) √√x²(1)² + y′(t)² + 2′(t)²³ dt
8. Surface Integrals
[F(x, y, z) - dx = [° R² + R$/ + d
dr
dt
[ 92,9,2) ds = [[ 9(2.9.1(2.9)) √ 12 + 12 + 1 dady
9. Flux Integrals For a surface with upward unit normal,
J.P.
11. Stokes' Theorem
= [[₁-Fife - Faly + Pa dyda
F-nds=
10. Gauss' (Divergence) Theorem
JIL V. FdV =
dv = [[₁, F
[[
F. ÂdS
(V x F). ÂdS=
s = [ F..
F.dr
Transcribed Image Text:1. Change of Variable of Integration in 2D [ f(x,y) drdy = f(z(u, v),y(u, 0)). («, ») ducho 2. Transformation to Polar Coordinates The useful formulas 3. Change of Variable of Integration in 3D [, (2, 2) dadydz = [[F(w, x, w)|J(u, v, w)| dududw 4. Transformation to Cylindrical Coordinates z=rcos, y=rsin, Jr.)=r 6. Line Integrals 5. Transformation to Spherical Coordinates x=rcos 0, y = rsin, ===, J(r,0,2)=r x=rcos@sind, y=rsin@sind, 2=rcoso, Jr.,0,0)=²sin 7. Work Integrals [1(x, y, z) ds = [ f(x(t), y(t),= (t)) √√x²(1)² + y′(t)² + 2′(t)²³ dt 8. Surface Integrals [F(x, y, z) - dx = [° R² + R$/ + d dr dt [ 92,9,2) ds = [[ 9(2.9.1(2.9)) √ 12 + 12 + 1 dady 9. Flux Integrals For a surface with upward unit normal, J.P. 11. Stokes' Theorem = [[₁-Fife - Faly + Pa dyda F-nds= 10. Gauss' (Divergence) Theorem JIL V. FdV = dv = [[₁, F [[ F. ÂdS (V x F). ÂdS= s = [ F.. F.dr
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