A) Find the following. Give your answers in 2-decimal places.IQR =Q3+1.5 IQR= Q1-1.5 IQR=B) Are There are outliers in this data set? Consider the following data set:1821222632353841434950545759636771737580828792939599103109111111113117119123123127129134 140141

The data is: 18,21, 22, 36, 32, 35, 38, 41, 43, 49, 50, 54, 57, 59, 63, 67, 71, 73, 75, 80, 82, 87,…

Answered: A) Find the following. Give your…

A) Find the following. Give your answers in 2-decimal places. IQR = Q3+1.5 IQR= Q1-1.5 IQR= B) Are There are outliers in this data set?

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

A) Find the following. Give your answers in 2-decimal places.

IQR =

Q3+1.5 IQR=
Q1-1.5 IQR=

B) Are There are outliers in this data set?

Consider the following data set:
18
21
22
26
32
35
38
41
43
49
50
54
57
59
63
67
71
73
75
80
82
87
92
93
95
99
103
109
111
111
113
117
119
123
123
127
129
134 140
141

Expert Solution

Given data,

The data is:

18,21, 22, 36, 32, 35, 38, 41, 43, 49, 50, 54, 57, 59, 63, 67, 71, 73, 75, 80, 82, 87, 92, 93, 95, 99, 103, 109, 111, 111, 113, 117, 119, 123, 123, 127, 129, 134, 140, 141

Step 1

Arrange the data in ascending form,

18,21, 22, 36, 32, 35, 38, 41, 43, 49, 50, 54, 57, 59, 63, 67, 71, 73, 75, 80, 82, 87, 92, 93, 95, 99, 103, 109, 111, 111, 113, 117, 119, 123, 123, 127, 129, 134, 140, 141

a) Here, number of terms is 40 (EVEN)

Now,

$\begin{array}{rcl} Median & = & \frac{((\frac{n}{2}) t h place value) + ((\frac{n}{2} + 1) t h place value)}{2} \\ = & \frac{(20 t h place value) + (21 t h place value)}{2} \\ = & \frac{80 + 82}{2} \\ = & 81 \end{array}$

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