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2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric
constants K
distance is d = 0.04 m. A potential difference of AV = 24 V is applied to the circuit.
(a) Find the equivalent capacitance of the system.
|(b) Find the potential AV1. (8=8.85×10-12 C²/N×m²)
2 and K, = 4, as shown in Figure. Parallel-plates have the area A =
0.8 m². The
%3D
A/2
AV1
A/2
A
K1
A/2
2d/3 d/3
K2
A/2
AV = 24 V
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