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A feed of a distillation column contains 40 mol% of n-pentane and 60 mol% of n-hexane will be separated to recover 92 mol% of n-pentane as distillate at the column condition of 1 atm. The column receives a saturated liquid feed with a flow rate of 1,200 kmol/h. A total condenser is used and reflux is a saturated liquid. Bottoms from the column contains 94 mol% of n-hexane from the feed. The carbon steel column is equipped with carbon steel sieve trays which have efficiency of 43%.

A feed of a distillation column contains 40 mol% of n-pentane and 60 mol% of n-hexane will be separated to recover 92 mol% of n-pentane as distillate at the column condition of 1 atm. The column receives a saturated liquid feed with a flow rate of 1,200 kmol/h. A total condenser is used and reflux is a saturated liquid. Bottoms from the column contains 94 mol% of n-hexane from the feed. The carbon steel column is equipped with carbon steel sieve trays which have efficiency of 43%.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A feed of a distillation column contains 40 mol% of n-pentane and 60 mol% of n-hexane will be separated to recover 92 mol% of n-pentane as distillate at the column condition of 1 atm. The column receives a saturated liquid feed with a flow rate of 1,200 kmol/h. A total condenser is used and reflux is a saturated liquid. Bottoms from the column contains 94 mol% of n-hexane from the feed. The carbon steel column is equipped with carbon steel sieve trays which have efficiency of 43%.


Determine the design specifications of the distillation column using the appropriate heuristics.


Hint: You need to find densities for vapour of distillate by using the chemical engineering principles that you have learnt. Use data in Table 2 and equation below to determine relative volatility of component.

αi = Yi/xi (1-yi)/(1-x₁) Table 2: Equilibrium data for n-pentane and n-hexane system at 1 atm. x = mole fraction of n-pentane in the liquid y = mole fraction of n-pentane in the vapor x = 0.00000, y = 0.00000, T(K) = 342.06 x = 0.05000, y = 0.12705, T(K) = 339.40 x = 0.10000, y = 0.23699, T(K) = 336.91 x = 0.15000, y = 0.33263, T(K) = 334.58 x = 0.20000, y = 0.41626, T(K) = 332.39 x = 0.25000, y = 0.48975, T(K) = 330.32 x = 0.30000 , y = 0.55462, T(K) = 328.38 x = 0.35000, y = 0.61214, T(K) = 326.53 x = 0.40000, y = 0.66335, T(K) = 324.79 x = 0.45000, y = 0.70911, T(K) = 323.14 x = 0.50000, y = 0.75016, T(K) = 321.56 x = 0.55000, y = 0.78711, T(K) = 320.07 x = 0.60000, y = 0.82048, T(K) = 318.64 x = 0.65000, y = 0.85070, T(K) = 317.28 x = 0.70000, y = 0.87816, T(K) = 315.97 x = 0.75000, y = 0.90317, T(K) = 314.72 x = 0.80000 , y = 0.92601, T(K) = 313.53 x = 0.85000, y = x = 0.90000, y = x = 0.95000, y = 0.94692, T(K) = 312.38 0.96610, T(K) = 311.28 0.98374, T(K) = 310.22 x = 1.00000, y = 1.00000, T(K) = 309.20
Transcribed Image Text:αi = Yi/xi (1-yi)/(1-x₁) Table 2: Equilibrium data for n-pentane and n-hexane system at 1 atm. x = mole fraction of n-pentane in the liquid y = mole fraction of n-pentane in the vapor x = 0.00000, y = 0.00000, T(K) = 342.06 x = 0.05000, y = 0.12705, T(K) = 339.40 x = 0.10000, y = 0.23699, T(K) = 336.91 x = 0.15000, y = 0.33263, T(K) = 334.58 x = 0.20000, y = 0.41626, T(K) = 332.39 x = 0.25000, y = 0.48975, T(K) = 330.32 x = 0.30000 , y = 0.55462, T(K) = 328.38 x = 0.35000, y = 0.61214, T(K) = 326.53 x = 0.40000, y = 0.66335, T(K) = 324.79 x = 0.45000, y = 0.70911, T(K) = 323.14 x = 0.50000, y = 0.75016, T(K) = 321.56 x = 0.55000, y = 0.78711, T(K) = 320.07 x = 0.60000, y = 0.82048, T(K) = 318.64 x = 0.65000, y = 0.85070, T(K) = 317.28 x = 0.70000, y = 0.87816, T(K) = 315.97 x = 0.75000, y = 0.90317, T(K) = 314.72 x = 0.80000 , y = 0.92601, T(K) = 313.53 x = 0.85000, y = x = 0.90000, y = x = 0.95000, y = 0.94692, T(K) = 312.38 0.96610, T(K) = 311.28 0.98374, T(K) = 310.22 x = 1.00000, y = 1.00000, T(K) = 309.20
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