A fast food outlet claims that the mean waiting time in line is less than 4.9 minutes. A random sample of 60 customers has a mean of 4.8 minutes with a standard deviation of 0.6 minute. If ? = 0.05, test the fast food outlet's claim. Using the above information, what are the null and alternate hypotheses? Ho : μ ≥4.9, Ha : μ <4.9Ho : μ ≥4.9, Ha : μ <4.9 Ho : μ ≥4.9, Ha : μ <4.9Ho : μ ≥4.9, Ha : μ <4.9 Ho : μ ≤4.9, Ha : μ >4.9Ho : μ ≤4.9, Ha : μ >4.9 Ho : μ ≤4.9, Ha : μ >4.9Ho : μ ≤4.9, Ha : μ >4.9 Ho : μ >4.9, Ha : μ =4.9Ho : μ >4.9, Ha : μ =4.9 Ho : μ >4.9, Ha : μ =4.9Ho : μ >4.9, Ha : μ =4.9 Ho : μ <4.9, Ha : μ ≥4.9

A fast food outlet claims that the mean waiting time in line is less than 4.9 minutes. A random sample of 60 customers has a mean of 4.8 minutes with a standard deviation of 0.6 minute. If ? = 0.05, test the fast food outlet's claim. Using the above information, what are the null and alternate hypotheses? Ho : μ ≥4.9, Ha : μ <4.9Ho : μ ≥4.9, Ha : μ <4.9 Ho : μ ≥4.9, Ha : μ <4.9Ho : μ ≥4.9, Ha : μ <4.9 Ho : μ ≤4.9, Ha : μ >4.9Ho : μ ≤4.9, Ha : μ >4.9 Ho : μ ≤4.9, Ha : μ >4.9Ho : μ ≤4.9, Ha : μ >4.9 Ho : μ >4.9, Ha : μ =4.9Ho : μ >4.9, Ha : μ =4.9 Ho : μ >4.9, Ha : μ =4.9Ho : μ >4.9, Ha : μ =4.9 Ho : μ <4.9, Ha : μ ≥4.9

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Description: A fast food outlet claims that the mean waiting time in line is less than 4.9 minutes. A random sample of 60 customers has a mean of 4.8 minutes with a standard deviation of 0.6 minute. If ? = 0.05, test the fast food outlet's claim. Using the above

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A health professional obtains records for 33 patients who have undergone a certain surgical procedure and finds the average length of stay is 3.23 days with a standard deviation of 1.58 days. Using a = evidence to suggest the actual average length of stay for this surgical procedure is 3 days? 0.10, is there What are the hypotheses? O Ho: µ = 3.23 vs H1: µ # 3.23 Ho:u = 3 vs H1 :µ#3 Họ : = %3D 3 vs H1: + 3 Ho: = 3.23 vs H1: + 3.23 %3D Calculate the test statistic using the correct letter. = - 0.84 t = 0.84 z = 0.84 = Z - 0.84 Determine the critical values. O+1.691 Q+1.694 ±1.307 +1.692 +1.282 土1.309 O+1.645
A health professional obtains records for 33 patients who have undergone a certain surgical procedure and finds the average length of stay is 5.79 days with a standard deviation of 1.37 days. Using a evidence to suggest the actual average length of stay for this surgical procedure is 5 days? What are the hypotheses? O Hoμ5 vs H₁ : μ #5 = Ho : x = 5 vs H₁ : x # 5 O H : |= 5.79 vs H1 : @#5.79 OHo5.79 vs H₁5.79 Calculate the test statistic using the correct letter. Oz= -3.31 Ot = 3.31 Ot= -3.31 Oz = 3.31 Determine the critical values. +2.576 +2.326 +2.449 ±2.739 ±2.733 ±2.728 +2.441 State your decision. O Accept Ho Fail to reject Ho Reject Ho days. = 0.01, is there The correct conclusion is that we Select an answer conclude that the average length of stay of all surgeries of this type Select an answer Select an answer What level of concern do you have for the validity of your results? O None = - our sample size is larger than 30 so there should be no problem with the conclusion Low - our…