A health professional obtains records for 33 patients who have undergone a certain surgical procedure a finds the average length of stay is 5.79 days with a standard deviation of 1.37 days. Using a = 0.01, is evidence to suggest the actual average length of stay for this surgical procedure is 5 days? What are the hypotheses? Hou 5 vs H₁ : μ ‡ 5 Ho: = 5 vs H₁ : x 5 Ho = 5.79 vs H₁ μ5.79 : Ho: 5.79 vs H₁5.79 : Calculate the test statistic using the correct letter. Oz = -3.31 Ot = 3.31 Ot= -3.31 Oz=3.31 Determine the critical values. +2.576 +2.326 +2.449 ±2.739 ±2.733 +2.728 +2.441 State your decision. O Accept Ho Fail to reject Ho
A health professional obtains records for 33 patients who have undergone a certain surgical procedure a finds the average length of stay is 5.79 days with a standard deviation of 1.37 days. Using a = 0.01, is evidence to suggest the actual average length of stay for this surgical procedure is 5 days? What are the hypotheses? Hou 5 vs H₁ : μ ‡ 5 Ho: = 5 vs H₁ : x 5 Ho = 5.79 vs H₁ μ5.79 : Ho: 5.79 vs H₁5.79 : Calculate the test statistic using the correct letter. Oz = -3.31 Ot = 3.31 Ot= -3.31 Oz=3.31 Determine the critical values. +2.576 +2.326 +2.449 ±2.739 ±2.733 +2.728 +2.441 State your decision. O Accept Ho Fail to reject Ho
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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![A health professional obtains records for 33 patients who have undergone a certain surgical procedure and
finds the average length of stay is 5.79 days with a standard deviation of 1.37 days. Using a
evidence to suggest the actual average length of stay for this surgical procedure is 5 days?
What are the hypotheses?
O Hoμ5 vs H₁ : μ #5
=
Ho : x = 5 vs H₁ : x # 5
O H : |= 5.79 vs H1 : @#5.79
OHo5.79 vs H₁5.79
Calculate the test statistic using the correct letter.
Oz= -3.31
Ot = 3.31
Ot= -3.31
Oz = 3.31
Determine the critical values.
+2.576
+2.326
+2.449
±2.739
±2.733
±2.728
+2.441
State your decision.
O Accept Ho
Fail to reject Ho
Reject Ho
days.
= 0.01, is there
The correct conclusion is that we Select an answer conclude that the average length of stay of all surgeries
of this type Select an answer Select an answer
What level of concern do you have for the validity of your results?
O None
=
- our sample size is larger than 30 so there should be no problem with the conclusion
Low - our sample size is near 30, so while that's likely sufficient for X to be approximately normally
distributed, seeing that the original data isn't extremely skewed would make us feel more comfortable
Extreme we should not use any part of what we've done to make a conclusion
O Moderate the original data is not normally distributed which is an assumptions violation](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffd31fdfb-4046-4b08-9c18-d73722d2496d%2Ff817589b-1af9-472b-a320-94ffe466b406%2F5oh2yyq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A health professional obtains records for 33 patients who have undergone a certain surgical procedure and
finds the average length of stay is 5.79 days with a standard deviation of 1.37 days. Using a
evidence to suggest the actual average length of stay for this surgical procedure is 5 days?
What are the hypotheses?
O Hoμ5 vs H₁ : μ #5
=
Ho : x = 5 vs H₁ : x # 5
O H : |= 5.79 vs H1 : @#5.79
OHo5.79 vs H₁5.79
Calculate the test statistic using the correct letter.
Oz= -3.31
Ot = 3.31
Ot= -3.31
Oz = 3.31
Determine the critical values.
+2.576
+2.326
+2.449
±2.739
±2.733
±2.728
+2.441
State your decision.
O Accept Ho
Fail to reject Ho
Reject Ho
days.
= 0.01, is there
The correct conclusion is that we Select an answer conclude that the average length of stay of all surgeries
of this type Select an answer Select an answer
What level of concern do you have for the validity of your results?
O None
=
- our sample size is larger than 30 so there should be no problem with the conclusion
Low - our sample size is near 30, so while that's likely sufficient for X to be approximately normally
distributed, seeing that the original data isn't extremely skewed would make us feel more comfortable
Extreme we should not use any part of what we've done to make a conclusion
O Moderate the original data is not normally distributed which is an assumptions violation
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