A fan is turned off, and its angular speed decreases from 10.0 rad/s to 6.3 rad/s in 5.0 s. What is the magnitude of the angular acceleration of the fan? 0.86 rad/s2 0.74 rad/s2 0.37 rad/s2 O 11.6 rad/s2 1.16 rad/s2

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Chapter1: Units, Trigonometry. And Vectors
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### Understanding Angular Acceleration

When a fan is turned off, its angular speed reduces over time. In this exercise, we examine how the angular speed of a fan decreases and calculate the angular acceleration. Angular acceleration can be defined as the rate of change of angular velocity and is measured in radians per second squared (rad/s²).

#### Problem Statement:
A fan is turned off, and its angular speed decreases from 10.0 rad/s to 6.3 rad/s in 5.0 seconds. What is the magnitude of the angular acceleration of the fan?

#### Given:
- Initial angular speed, \( \omega_0 = 10.0 \) rad/s
- Final angular speed, \( \omega = 6.3 \) rad/s
- Time interval, \( t = 5.0 \) seconds

#### Formula:
The angular acceleration \( \alpha \) is calculated using the formula:
\[ \alpha = \frac{\Delta \omega}{\Delta t} \]
where \( \Delta \omega \) is the change in angular speed and \( \Delta t \) is the time interval.

#### Calculation:
\[ \alpha = \frac{6.3 \, \text{rad/s} - 10.0 \, \text{rad/s}}{5.0 \, \text{s}} \]
\[ \alpha = \frac{-3.7 \, \text{rad/s}}{5.0 \, \text{s}} \]
\[ \alpha = -0.74 \, \text{rad/s}^2 \]

Since we are asked for the magnitude of the angular acceleration, we take the absolute value:
\[ |\alpha| = 0.74 \, \text{rad/s}^2 \]

#### Answer Choices:
- ○ 0.86 rad/s²
- ○ 0.74 rad/s²
- ○ 0.37 rad/s²
- ○ 11.6 rad/s²
- ○ 1.16 rad/s²

The correct answer is:
- ○ **0.74 rad/s²**

### Conclusion
By using the change in angular speeds and the time interval, we determined the magnitude of the angular acceleration of the fan is 0.74 rad/s². This process demonstrates the method of calculating angular acceleration when the initial and final angular speeds, along with the time interval, are known.
Transcribed Image Text:### Understanding Angular Acceleration When a fan is turned off, its angular speed reduces over time. In this exercise, we examine how the angular speed of a fan decreases and calculate the angular acceleration. Angular acceleration can be defined as the rate of change of angular velocity and is measured in radians per second squared (rad/s²). #### Problem Statement: A fan is turned off, and its angular speed decreases from 10.0 rad/s to 6.3 rad/s in 5.0 seconds. What is the magnitude of the angular acceleration of the fan? #### Given: - Initial angular speed, \( \omega_0 = 10.0 \) rad/s - Final angular speed, \( \omega = 6.3 \) rad/s - Time interval, \( t = 5.0 \) seconds #### Formula: The angular acceleration \( \alpha \) is calculated using the formula: \[ \alpha = \frac{\Delta \omega}{\Delta t} \] where \( \Delta \omega \) is the change in angular speed and \( \Delta t \) is the time interval. #### Calculation: \[ \alpha = \frac{6.3 \, \text{rad/s} - 10.0 \, \text{rad/s}}{5.0 \, \text{s}} \] \[ \alpha = \frac{-3.7 \, \text{rad/s}}{5.0 \, \text{s}} \] \[ \alpha = -0.74 \, \text{rad/s}^2 \] Since we are asked for the magnitude of the angular acceleration, we take the absolute value: \[ |\alpha| = 0.74 \, \text{rad/s}^2 \] #### Answer Choices: - ○ 0.86 rad/s² - ○ 0.74 rad/s² - ○ 0.37 rad/s² - ○ 11.6 rad/s² - ○ 1.16 rad/s² The correct answer is: - ○ **0.74 rad/s²** ### Conclusion By using the change in angular speeds and the time interval, we determined the magnitude of the angular acceleration of the fan is 0.74 rad/s². This process demonstrates the method of calculating angular acceleration when the initial and final angular speeds, along with the time interval, are known.
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