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a) Explain the significance of the binding energy of an isotope. b) Use the data to explain why potassium-42 is a beta minus emitter but potassium-39 cannot undergo beta minus decay.

a) Explain the significance of the binding energy of an isotope. b) Use the data to explain why potassium-42 is a beta minus emitter but potassium-39 cannot undergo beta minus decay.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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a) Explain the significance of the binding energy of an isotope. b) Use the data to explain why potassium-42 is a beta minus emitter but potassium-39 cannot undergo beta minus decay.
The table shows two isotopes of potassium and two isotopes of calcium. 39K 42K Stable B-decay 38.96371 41.9624 19 19 23 42.34797 0.38557 5.76 x 10-11 Type of emission Mass of neutral atom / u Number of electrons Number of protons Number of neutrons Total mass / u Mass defect / u Binding energy / J Mass of the electron = 0.000549 u Mass of the proton = 1.007276 u Mass of the neutron = 1.008665 u 39 Ca B+ decay 38.9707 42Ca stable 41.95863
Transcribed Image Text:The table shows two isotopes of potassium and two isotopes of calcium. 39K 42K Stable B-decay 38.96371 41.9624 19 19 23 42.34797 0.38557 5.76 x 10-11 Type of emission Mass of neutral atom / u Number of electrons Number of protons Number of neutrons Total mass / u Mass defect / u Binding energy / J Mass of the electron = 0.000549 u Mass of the proton = 1.007276 u Mass of the neutron = 1.008665 u 39 Ca B+ decay 38.9707 42Ca stable 41.95863
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