(a) dx (x - 3)5 The integral is not improper. Since y=- has a vertical asymptote at x=2, the integral is improper. (x - 3)5 O Since the integral has an infinite interval of integration, the integral is improper. O Since y= has a vertical asymptote at x=3, the integral is improper. (x - 3)5 r10 (b) 4In(x) dx Since y=In(x) has a vertical asymptote at x=1, the integral is improper. O Since y=In(x) has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper. O The integral is not improper. (c) sec(x) dx Jo O The integral is not improper. O Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper. O Since y=sec(x) has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper. (d) xp (x-5)3 The integral is not improper. 1 has a vertical asymptote at x=5, the integral is improper. O Since y= (x-5)3 O Since y=- (x-5)3 has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper.
(a) dx (x - 3)5 The integral is not improper. Since y=- has a vertical asymptote at x=2, the integral is improper. (x - 3)5 O Since the integral has an infinite interval of integration, the integral is improper. O Since y= has a vertical asymptote at x=3, the integral is improper. (x - 3)5 r10 (b) 4In(x) dx Since y=In(x) has a vertical asymptote at x=1, the integral is improper. O Since y=In(x) has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper. O The integral is not improper. (c) sec(x) dx Jo O The integral is not improper. O Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper. O Since y=sec(x) has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper. (d) xp (x-5)3 The integral is not improper. 1 has a vertical asymptote at x=5, the integral is improper. O Since y= (x-5)3 O Since y=- (x-5)3 has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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