(a) dx (x - 3)5 The integral is not improper. Since y=- has a vertical asymptote at x=2, the integral is improper. (x - 3)5 O Since the integral has an infinite interval of integration, the integral is improper. O Since y= has a vertical asymptote at x=3, the integral is improper. (x - 3)5 r10 (b) 4In(x) dx Since y=In(x) has a vertical asymptote at x=1, the integral is improper. O Since y=In(x) has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper. O The integral is not improper. (c) sec(x) dx Jo O The integral is not improper. O Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper. O Since y=sec(x) has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper. (d) xp (x-5)3 The integral is not improper. 1 has a vertical asymptote at x=5, the integral is improper. O Since y= (x-5)3 O Since y=- (x-5)3 has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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r3
(a)
2 (x – 3)5
dx
The integral is not improper.
Since y=
has a vertical asymptote at x=2, the integral is improper.
(x – 3)5
Since the integral has an infinite interval of integration, the integral is improper.
O Since y=
has a vertical asymptote at x=3, the integral is improper.
(x – 3)5
10
(b)
4ln(x) dx
O Since y=In(x) has a vertical asymptote at x=1, the integral is improper.
O Since y=In(x) has a vertical asymptote at x=0, the integral is improper.
O Since the integral has an infinite interval of integration, the integral is improper.
O The integral is not improper.
/4
(c)
sec(x) dx
O The integral is not improper.
O Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper.
Since y=sec(x) has a vertical asymptote at x=0, the integral is improper.
Since the integral has an infinite interval of integration, the integral is improper.
1
(d)
dx
(x-5)3
8.
The integral is not improper.
Since y=-
(x-5)
has a vertical asymptote at x=5, the integral is improper.
3
Since y=-
(x-5)3
has a vertical asymptote at x=0, the integral is improper.
O Since the integral has an infinite interval of integration, the integral is improper.
Transcribed Image Text:r3 (a) 2 (x – 3)5 dx The integral is not improper. Since y= has a vertical asymptote at x=2, the integral is improper. (x – 3)5 Since the integral has an infinite interval of integration, the integral is improper. O Since y= has a vertical asymptote at x=3, the integral is improper. (x – 3)5 10 (b) 4ln(x) dx O Since y=In(x) has a vertical asymptote at x=1, the integral is improper. O Since y=In(x) has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper. O The integral is not improper. /4 (c) sec(x) dx O The integral is not improper. O Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper. Since y=sec(x) has a vertical asymptote at x=0, the integral is improper. Since the integral has an infinite interval of integration, the integral is improper. 1 (d) dx (x-5)3 8. The integral is not improper. Since y=- (x-5) has a vertical asymptote at x=5, the integral is improper. 3 Since y=- (x-5)3 has a vertical asymptote at x=0, the integral is improper. O Since the integral has an infinite interval of integration, the integral is improper.
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