= [ (23a)" e1¹0z da, Consider the integral n is a natural number greater than 1, When applying integration by parts of J, you get : O a) 10 ((23)² e1¹0² +nf (23a)¹-¹ e¹ e10x dx O b) n 10 ((23a)"e10 -nf (23a)"-¹e1¹0z dz) е 00) n-1 10x dx O c) 23¹² 10 (²+²) " e n n-1 e10x dx O d) 30 ( 20" 10² _ n f 2²-1 23" 10 - J

Q: L ܛ 2 [T+ ] 3 + 16% ܓ

A: Given integral:- L=∫0131+16x212dx

Q: 17) Calculate the indefinite integral S-5dx √4-16x² 16) Evaluate the definite integral Š - 0 3…

A: 16).17).

Q: Find the indefinite integrals: (a) S dx x+1 + C. (b) S da = 23 x2+1 =

A: SOLUTION-

Q: [7] Use long division and complete the square to solve the following integral. x² - 4x-2 dx x² -…

A: Explanation of the answer is as follows

Q: 4x + 4 -dx. Choose all of the following that are correct. x² + 1 Consider the definite integral

A: To evaluate: ∫014x+4x2+1 dx Solution: We know that, ∫f'xfxdx=lnfx+C ∫1x2+a2dx=1atan-1xa+C

Q: I got to the step where I have (5h/h-1)/h. I think I can multimply (5h/h-1) by (h/1). This results…

A: We have to find actual expression for the given expression.

Q: d b) [ 4e*(In x) ] dx

A:

Q: 16 = dx / x7 3/5+4x⁹

A: This question has been solved without using trigonometric substitution