A drug is used to help prevent blood clots in certain patients. In clinical​ trials, among 4178 patients treated with the​ drug, 115 developed the adverse reaction of nausea. Construct a 90​% confidence interval for the proportion of adverse reactions. ​a) Find the best point estimate of the population proportion p.     ​b) Identify the value of the margin of error E.       ​c) Construct the confidence interval.     ​d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.

Q: Assume that population proportion is to be estimated from the sample described. Use the sample…

A: sample size(n)=515sample proportion=0.20Confidence level=95%

Q: A drug is used to help prevent blood clots in certain patients. In clinical​ trials, among 4284…

A: The question is about confidence intervalGiven :Total no. of patients who were treated with the drug…

Q: Pulse Rates: Pulse rate is an important measure of fitness of a person's cardiovascular system. The…

A: Given that Sample size(n)=21 Sample mean x̄=53.6 Sample standard deviation(s) =3.23  We have to find…

Q: Find the indicated margin of error. Out of 260 trials, 150 turned out positive. Find the margin of…

A: It is given that the sample size (n) is 260 and the number of positive trials (x) is 150.

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given: n= 1031 ,x= 545 need to find point estimation for p.

Q: Construct a 95% confidence interval of the mean pulse rate for adult males

A: Given,       Males      Females 86 71 80 85 72 62 91 82 50 74 60 72 57 69 66 75 52 55…

Q: Construct the confidence interval for the population mean y. C=0.95, x= 16.7, o= 4.0, and n= 75. A…

A: Here, C=0.95, x=16.7, σ=4.0, and n=75.

Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a study…

A:

Q: In a survey of 3700 TV viewers, 834 said they watch network news programs. Find the margin of error…

A: Solution

Q: C. Find the length of the confidence interval given the following data: 1.s = 4.5, n = 20,…

A: Here use formula of length of confidence interval

Q: Find the margin of error for the 95% confidence interval used to estimate the population proportion.…

A: Confidence level = 95% Sample size (n) = 2440 Sample proportion (p̂) = 0.70

Q: n your random sample of home prices. To insert a tion" or simply copy and edit the equation in the…

A: Formula : The confidence interval formula is CI =

Q: In a clinical trial of a certain​ drug, 30 subjects experience headaches among the 221 subjects…

A: given data n = 221x = 30construct 99% ci for p.

Q: A random sample of 320 medical doctors showed that 162 had a solo practice. Let p represent the…

A: Given,

Q: Use the sample data and confidence level given below to complete. A drug is used to help prevent…

A: The random variable adverse reaction follows binomial distribution. X ~ B (n, p) The number of…

Q: A department chair wanted to know whose students performed better on a common pass/fail final exam:…

A: p1 :  proportion of students passed in smith's  class p2 :  proportion of students passed in Jones's…

Q: A public health official in Martin county needs to estimate the average diastolic blood pre…

A: Given: Sample size(n)=132Meanx¯=89Population standard deviationσ=10

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A drug is…

A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts.  In case…

Q: In a clinical trial of a certain drug, 27 subjects experience headaches among the 219 subjects…

A: From the given information,

Q: A​ 95% confidence interval for the proportion of U.S. adults who subscribe to some sort of streaming…

A: In the above question, we are given,  a confidence interval is

Q: A SURVEY WAS CONDUCTED IN 2010 AND 2020. THE 2010 RESULTS SUMMARIZED THE RESPONSI WHEREAS THE…

A: The given table is HEALTH ISSUE 2010 SURVEY 2020 SURVEY ATE RECOMMEND AMOUNT OF FIBROUS…

Q: The number of successes and the sample size are given for a simple random sample from a population.…

A: Obtain the value of sample proportion. The value of sample proportion is obtained below: From the…

Q: Use the given data to construct a confidence interval of the requested level. X = 178, N=531,…

A: Given : Sample Size, n = N = 531 Number of successes, x = 178

Q: Find the point estimate of the percentage of men who have red/green color blindness. b. Find a 90%…

A: Given that sample size n = 80 Number of men who have red/green color blindness, X = 7 At 90%…

Q: Part a and b

A:

Q: FIND t a n = 15 for the 98% confidence interval for the mean.

A: Provided information that, n=15 Alpha (α)=1-0.98=0.02 α/2=0.01

Q: Use the sample data and confidence level given below to complete parts​ (a) through​ (d). Round to…

A: Note: Hey, since there are multiple subparts are posted, we will answer first three subparts for…

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.

Q: A student organization conducted a statistical study to calculate a 95% confidence interval for the…

A: Hence,

Q: What is the confidence interval? Select the correct choice below and, if necessary, fill in the…

A: Mean = 56.64 Standard deviation = 14.598 n=100

Q: Ciency: 1. The score on the chapter 8 test is compared with a student's chapter 2 test score. The…

A: (a)Step by step procedure to obtain the test statistic using MINITAB software is given below:Choose…

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

A:

Q: Determine the margin of error. It has been determined with 95% confidence that the proportion of…

A: Given: 95% confidence interval is (0.78, 0.82) So, Lower limit = 0.78 Upper limit = 0.82

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A drug is…

A:

Q: Using the data attached, construct confidence intervals:  1. using the data provided, construct a…

A:

Q: Use the confidence level and sample data to find the margin of error E. Systolic blood pressures for…

A:

Q: Sally is analyzing wheat production. She sampled 700 wheat farmers from across the state. She found…

A:

Q: A SURVEY WAS CONDUCTED IN 2010 AND 2020. THE 2010 RESULTS SUMMARIZED T WHEREAS THE RESULTS OF THE…

A:

Q: Find the margin of error for the​ 99% confidence interval used to estimate the population…

A: p^ : Sample Proportion 35% of the patients showed improvement. So, probability that a patient shows…

Q: According to a telephone survey of adults, 86% of homeowners said that owning a home was a good…

A: From the given information, According to a telephone survey of adults, 86% of homeowners said that…

Q: identify the t-score for a 90% confidence interval if the sample size is 31.        t=

A:

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A drug is…

A: Note: I have rounded all final answers to 3 d.p. as it wasn't specified for part (b) and (c)

Q: In a survey, 1000 Grade 7 students were asked if they read storybooks. There were 318 who said Yes.…

A: Givenn=1000x=318p^=3181000=0.318Confidence interval = 95%

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.